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Korolek [52]
3 years ago
13

Translate into an algebraic expression and simplify if possible. C It would take Maya x minutes to rake the leaves and Carla y m

inutes, what portion of the leaves do they rake in one minute if they work together?
Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

in one minute they rake \frac{y+x}{xy} leaves working together.

Step-by-step explanation:

If Maya rakes the leaves in x minutes, then, in one minute she rakes \frac{1}{x} leaves.

In the case of Carla, if she rakes the leaves in y minutes, in one minute she rakes \frac{1}{y} leaves.

Therefore, to know the portion of leaves they can rake in one minute working together, we need to sum up both of the portions each one of them rake in one minute, this gives us: \frac{1}{x}+ \frac{1}{y}

Now, to simplify this expression:

\frac{1}{x}+ \frac{1}{y}  =\frac{y+x}{xy}

Thus, in one minute they rake \frac{y+x}{xy} leaves.

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(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

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Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

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