Question

The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 + xz2 + yz – 24.

Answer 1

x is equal to 5 and y is equal to 29

Answer 2

Answer:

$\text{The value of x and y is } x=5, y=29$      

Step-by-step explanation:

Given the product of two expressions

$4z^2+7z-8\text{ and }-z+3\text{ is }-4z^3+xz^2+yz-24$

we have to find the value of x and y

First we find the product of

$4z^2+7z-8\text{ and }-z+3$

$(4z^2+7z-8)(-z+3)$

Opening the brackets

$4z^2(-z+3)+7z(-z+3)-8(-z+3)$

Using distributive property, a.(b+c)=a.b+a.c

$(-4z^3+12z^2)+(-7z^2+21z)+(8z-24)$

Combining like terms

$-4z^3+(12z^2-7z^2)+(21z+8z)-24$

$-4z^3+5z^2+29z-24$

which is required product.

$\text{Now compare above product with given product }-4z^3+xz^2+yz-24$

$x=5, y=29$