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tigry1 [53]
2 years ago
15

In 1999, there were 9860 Great Danes registered with the American Kennel Club. The number of registered Labrador Retrievers was

6997 more than fifteen times the number of registered Great Danes. How many registered Labrador Retrievers were there? Explain all of your work.
Mathematics
2 answers:
jekas [21]2 years ago
7 0

Answer:

153,997 Labrador Retrievers

Step-by-step explanation:

Let's make an equation for this problem. We know that there were 9,860 Great Danes. The number of Labrador Retrievers was 6,997 more than 15 times the number of registered Great Danes. More than can be changed to a plus sign. 15 times the number of Great Danes is 15 times 9,860. The equation is now 15*9,860 + 6,997.

15*9,860 is 147,900

147,900 + 6,997 is 153,997.

horsena [70]2 years ago
4 0
This is true, good job
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6 2/3 + 1 5/6 = 8 1/2

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If x^2 = 10, what is the value of x?
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X^2=10
x=3.16 (3sig.figs)

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3 years ago
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Manuel made at least one error as he found the value of this expression. Identify the step in which Manuel made his first error.
tamaranim1 [39]

Answer:

Manuel made his first mistake in step 2 leading to the continuous mistakes

Final answer=185

Step-by-step explanation:

Manuel made at least one error as she found the value of this expression. 2(-20) + 3[5/4(-20)] + 5[2/5(50)] + 4(50) Step 1: 2(-20) + 3(-25) + 5(20) + 4(50) Step 2: (3 + 2)(-20 + -25) + (5 + 4)(20 + 50) Step 3: 5(-45) + 9(70) Step 4: -225 + 630 Step 5: 405 Identify the step in which Chris made her first error. After identifying the step with the first error, write the corrected steps and find the final answer.

2(-20) + 3[5/4(-20)] + 5[2/5(50)] + 4(50)

Step 1: 2(-20) + 3(-25) + 5(20) + 4(50)

Step 2: -40 - 75 + 100 +

200

Step 3: -115 + 300

Step 4: 185

Manuel made his first error in step 2 by combining two different terms into one as he has done

(3 + 2)(-20 + -25) and also (5 + 4)(20 + 50)

Step 2: (3 + 2)(-20 + -25) + (5 + 4)(20 + 50)

Step 3: 5(-45) + 9(70) Step 4: -225 + 630 Step 5: 405

He should have evaluated the terms separately as I have done above, giving us 185 as the final answer in contrast to his 405 final answer.

5 0
2 years ago
Please help!!!!
valentina_108 [34]
ANSWER

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t  + 6}{ t + 2}
where,
t \ne - 2



EXPLANATION

We want to simplify the rational expression

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }


We can observe that the numerator of the given rational expression is a quadratic trinomial and the denominator is a difference of two squares



We need to split the middle term in the numerator and rewrite the denominator as a difference of two squares to obtain,




\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{{t}^{2}  + 6t - 2t - 12}{ {t}^{2}  -  {2}^{2} }



We now factor to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t (t+ 6) - 2(t  + 6)}{ (t  -  2)(t + 2)}


This implies that,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t - 2) (t  + 6)}{ (t  -  2)(t + 2)}


We now cancel out common factors to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t  + 6)}{ (t + 2)}


The restriction is that, the denominator cannot be zero.

Thus

t + 2 \ne0


This implies that,

t  \ne - 2
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Answer:

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Step-by-step explanation:

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