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tigry1 [53]
3 years ago
15

In 1999, there were 9860 Great Danes registered with the American Kennel Club. The number of registered Labrador Retrievers was

6997 more than fifteen times the number of registered Great Danes. How many registered Labrador Retrievers were there? Explain all of your work.
Mathematics
2 answers:
jekas [21]3 years ago
7 0

Answer:

153,997 Labrador Retrievers

Step-by-step explanation:

Let's make an equation for this problem. We know that there were 9,860 Great Danes. The number of Labrador Retrievers was 6,997 more than 15 times the number of registered Great Danes. More than can be changed to a plus sign. 15 times the number of Great Danes is 15 times 9,860. The equation is now 15*9,860 + 6,997.

15*9,860 is 147,900

147,900 + 6,997 is 153,997.

horsena [70]3 years ago
4 0
This is true, good job
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Find the next term is in the explicit and recursive rule for the in term of the sequence. NO LINKS!!!
BARSIC [14]

9514 1404 393

Answer:

  5) 729, an=3^n, a[1]=3; a[n]=3·a[n-1]

  6) 1792, an=7(4^(n-1)), a[1]=7; a[n]=4·a[n-1]

Step-by-step explanation:

The next term of a geometric sequence is the last term multiplied by the common ratio. (This is the basis of the recursive formula.)

The Explicit Rule is ...

  a_n=a_1\cdot r^{n-1}

for first term a₁ and common ratio r.

The Recursive Rule is ...

  a[1] = a₁

  a[n] = r·a[n-1]

__

5. First term is a₁ = 3; common ratio is r = 9/3 = 3.

Next term: 243×3 = 729

Explicit rule: an = 3·3^(n-1) = 3^n

Recursive rule: a[1] = 3; a[n] = 3·a[n-1]

__

6. First term is a₁ = 7; common ratio is r = 28/7 = 4.

Next term: 448×4 = 1792

Explicit rule: an = 7·4^(n-1)

Recursive rule: a[1] = 7; a[n] = 4·a[n-1]

7 0
3 years ago
Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o
Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box=12 m^3

height is 3 times the width

let height, length and breadth be H, L & B

H=3\times B

V=12=L\times B\times H

4=B^2\times L[/tex]

L=\frac{4}{B^2}

Cost of side walls $ 8/m^2

Cost of base $ 12/m^2

Cost of side walls=(2LH+2BH)\cdot 8

Cost of base =12LB

Total cost C=16LH+16BH+12LB

C=48LB+48B^2+12LB

C=\frac{192}{B}+48B^2+\frac{48}{B}

differentiate C w.r.t B to get minimum cost

\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}

B^3=\frac{240}{2\times 48}

B=1.35 m

H=3\times 1.35=4.07 m

L=2.19 m

C=$ 265.25

3 0
3 years ago
Chris saved x dollars and spent half of his savings buying video games. After earning an additional $15 cutting grass, he had $5
olga55 [171]

Chris started with $70  in the savings account

What is the equation representing the scenario?

The equation representing the scenario painted in the question is: one half times x plus 15 equals 50

1/2*X+15=50

X/2+15=50

X/2=50-15

X/2=35

X=35*2

X=70

In short the amount Chris started with in the savings account is $70

Find out more about savings plan equation on:brainly.com/question/23630456

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4 0
1 year ago
Just need to check these answers
amid [387]
Great Job! they are all correct.  :)


Good luck in your next tests.
3 0
3 years ago
7.91 rounded to the nearest hundreth
olasank [31]

The value of 7.91 rounded to the nearest hundredth as in the task content is; 7.91.

<h3>What is the value of 7?91 rounded to the nearest hundredth?</h3>

It follows from the task content that it is required that the decimal number 7.91 be rounded to the nearest hundredth.

Since the hundredth place value belongs to the second digit to the right of the decimal, it follows that the digit, 1 holds the hundredth place value and since no other digits come after, the number remains the same.

Read more on rounding off;

brainly.com/question/12263092

#SPJ1

4 0
2 years ago
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