Evaluat the exression when X is equal to3 X+1

Mathematics

1 answer:

Gemiola [76]3 years ago

4 0

Just substitute 3 for x, and it’s 3+1=4. Your answer is 4!

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The sales tax on the purchase of a futon is $24.45. If the tax rate is 5%, find the purchase price of the futon

12345 [234]

5% is the same as .05, so in this case, the sales tax is added by .05. Subtract .05 from 24.45 to get the original price of the futon. You'll get $24.40

7 0

3 years ago

Read 2 more answers

5/6v+10=5 what is the answer

yulyashka [42]

Answer:

x= -3/2

Step-by-step explanation:

You would multiply both sides by 6x+10 and then that would give you 5-5)6x+10) and you would divide both sides by 5. This would give you 1=6x+10, you would then try to isolate the 6x giving you -6x=10-1 or -6x=9 and you would see if the solutions are in the defined ranges so x=-5/3 is NOT in the defined range but x=-3/2 is.

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3 years ago

Solve for the variable a D =a+b-c/3

yuradex [85]

Hey there,
solving for a is just like you think of all other letter as a constant
i.e the only variable is a
so you need to subtract b as a start
d=a+b-c/3
-b -b
=============

-b+d=a-c/3 now it's time to add c/3 (isolate a by itself in one side)

-b+d=a-c/3
+c/3 +c/3
==============
c/3-b+d=a

Hence you have solved for a

4 0

4 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$