X^-n = 1/x^n
Your fraction becomes:
1/ {(m^5 t^2)(27m^6t^3)} now combine the powers in the denominator
1/ (27 m^11 t^5)
Group and factor
group y's with y's and z's with z's
(y²-10y)+(10z-yz)
factor
y(y-10)+z(10-y)
force undistribute -1
-y(10-y)+z(10-y)
factor
(10-y)(-y+z)
(z-y)(10-y) or
(y-z)(y-10)
The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
<h3>What is the interest rate behind a pay back?</h3>
In this situation we assume that the loan does not accumulate interests continuously in time. Hence, the <em>interest</em> rate for paying the loan back 75 days later is:
575 = 525 · (1 + r/100)
50 = 525 · r /100
5000 = 525 · r
r = 9.524
The loan has an <em>interest</em> rate of 9.524 % for 75 days. <em>Simple annual interest</em> rate is determine by rule of three:
r' = 9.524 × 365/75
r' = 46.350
The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
To learn more on interests: brainly.com/question/26457073
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Answer:
The simple solutions are:
Right 6: (-2+6,-3) = (4,3)
Left 6: (-2-6,-3) = (-8,-3)
Up 6: (-2,-3+6) = (-2, 3)
Down 6: (-2,-3-6) = (-2,-9)
Those are for horizontal or vertical
line segments.
Step-by-step explanation: