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givi [52]
1 year ago
14

Write using exponential notation? 5.5.2.2.2.2

Mathematics
1 answer:
inna [77]1 year ago
4 0

Answer:

5 ^{2}  \times 2^{4}

Step-by-step explanation:

Multiplying 5 by itself is the same thing as raising it to the second power:

5 \times 5 = {5}^{2}  = 25

We multiply 2 by itself two seperate times. That's the same thing as raising 2 to the second power to the second power or in simpler terms raising two to the fourth power:

2 \times 2 \times 2 \times 2 = {({2}^{2})}^{2}  =  {2}^{4}  = 16

Since only multiplication is present, we can combine the two terms to get:

5^{2}  \times  {2}^{4}

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tan theta=[opposite]/[adjacent]
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thus
tan 37=17/x
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x=22.56 ft
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Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
2 years ago
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