Question

an NHL hockey player (m=90 kg) stands motionless on the ice . the 10 kg stanley cup is thrown to the player at 4m/s. after he catches the cup determine the speed of the player cup combination. assuming there is no friction between the skates and the ice?

Answer 1

Answer:v=0.4 m/s

Explanation:

Mass hockey player $m_1=90 kg$

mass of  cup $m_2=10 kg$

Velocity of cup $u=4 m/s$

let v be the velocity of the combined system

Conserving momentum

$m_1\cdot 0+m_2u=(m_1+m_2)v$

$v=\frac{10\times 4}{100}$

$v=\frac{40}{100}$

$v=0.4 m/s$