Question

Suppose that a sound has initial intensity β1 measured in decibels. This sound now increases in intensity by a factor f. What is the new level of sound β2?

Answer 1

Answer:

β2= β1+10*f

Explanation:

comparing β2 and β1, it is said that β2 is increased by a factor of f.

for each factor of f, there is a 10*f dB increase.

therefore if the β1 is increases by an intensity of factor f

the new intensity would be β1+ 10*f