Reactants
C8H18
O2
Products
CO2
H2O
Answer: -31.36 m/s
Explanation:
This is a problem of motion in one direction (specifically vertical motion), and the equation that best fulfills this approach is:
(1)
Where:
is the final velocity of the supply bag
is the initial velocity of the supply bag (we know it is zero because we are told it was "dropped", this means it goes to ground in free fall)
is the acceleration due gravity (the negtive sign indicates the gravity is downwards, in the direction of the center of the Earth)
is the time
Knowing this, let's solve (1):
(2)
Finally:
Note the negative sign is because the direction of the bag is downwards as well.
a) The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):

It is given:
v = 8.5 m/s
m = 91 kg
So:

b) We can calculate height by using the formula for potential energy (PE):
PE = m*g*h
In this case, h is eight, and PE is the same as KE:
PE = KE = 3,287.4 J
m = 91 kg
g = 9.81 m/s² - gravitational acceleration
h = ? - height
Now, let's replace those:
3,287.4= 91 * 9.81 * h
⇒ h = 3,287.4/(91*9.81) = 3,287.4/892.7 = 3.7 m
Answer:
D. Exothermic, because energy is being absorbed from the surroundings
Explanation:
This is true about the Exothemic reaction due to the fact that, the reaction occurs outside the body. During this reaction, the energy being absorbed <em>from the surrounding environment will hit the body surface thereby creating the coldness due to the heat given out from the body being minimal.</em>
Answer:
=6.5%
Explanation:
Mass of the ball:
]
Initial velocity of the ball: 
final velocity of the ball:
which is -30/100 of
=
Mass of the bottle: 
Initial velocity of the bottle: 
final velocity of the bottle:
is unknown (to find)
<em>by using conservation momentum, which stated that the initial momentum is equal to the final momentum.</em>
<em />
<em />
<em>so since the bottle is at rest firstly, therefore </em>
<em />
<em />
<em />
<em />
<em> </em><em>equation 1</em>
so now substitute
into equation 1

<em />
<em />
<em>collect the like terms</em>


divide both side by 

Now substitute

6.5%
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