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3 years ago

What is measurements?

Physics

2 answers:

vitfil [10]3 years ago

5 0

Answer:

the process of comparison of an unknown quality with a know standard quantity is called measurement

Sliva [168]3 years ago

3 0

Answer:

the action of measuring something.

Measurement is a comparison of an unknown quantity with a known fixed quantity of the same kind. The value obtained on measuring a quantity is called its magnitude. Magnitude of a quantity is expressed as numbers in its units.

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How many revolutions per minute would a 23 m -diameter Ferris wheel need to make for the passengers to feel "weightless" at the

kirza4 [7]

Answer:

Approximately $6.2\; {\rm rpm}$ , assuming that the gravitational field strength is $g = 9.81\; {\rm m\cdot s^{-2}}$ .

Explanation:

Let $\omega$ denote the required angular velocity of this Ferris wheel. Let $m$ denote the mass of a particular passenger on this Ferris wheel.

At the topmost point of the Ferris wheel, there would be at most two forces acting on this passenger:

Weight of the passenger (downwards), $m\, g$ , and possibly
Normal force $F_\text{normal}$ that the Ferris wheel exerts on this passenger (upwards.)

This passenger would feel "weightless" if the normal force on them is $0$ - that is, $F_\text{normal} = 0$ .

The net force on this passenger is $(m\, g - F_\text{normal})$ . Hence, when $F_\text{normal} = 0$ , the net force on this passenger would be equal to $m\, g$ .

Passengers on this Ferris wheel are in a centripetal motion of angular velocity $\omega$ around a circle of radius $r$ . Thus, the centripetal acceleration of these passengers would be $a = \omega^{2}\, r$ . The net force on a passenger of mass $m$ would be $m\, a = m\, \omega^{2}\, r$ .

Notice that $m\, \omega^{2} \, r = (\text{Net Force}) = m\, g$ . Solve this equation for $\omega$ , the angular speed of this Ferris wheel. Since $g = 9.81\; {\rm m\cdot s^{-2}}$ and $r = 23\; {\rm m}$ :

$\begin{aligned} \omega^{2} = \frac{g}{r}\end{aligned}$ .

$\begin{aligned} \omega &= \sqrt{\frac{g}{r}} \\ &= \sqrt{\frac{9.81\; {\rm m \cdot s^{-2}}}{23\; {\rm m}}} \\ &\approx 0.653\; {\rm rad \cdot s^{-1}} \end{aligned}$ .

The question is asking for the angular velocity of this Ferris wheel in the unit ${\rm rpm}$ , where $1\; {\rm rpm} = (2\, \pi\; {\rm rad}) / (60\; {\rm s})$ . Apply unit conversion:

$\begin{aligned} \omega &\approx 0.653\; {\rm rad \cdot s^{-1}} \\ &= 0.653\; {\rm rad \cdot s^{-1}} \times \frac{1\; {\rm rpm}}{(2\, \pi\; {\rm rad}) / (60\; {\rm s})} \\ &= 0.653\; {\rm rad \cdot s^{-1} \times \frac{60\; {\rm s}}{2\, \pi\; {\rm rad}} \times 1\; {\rm rpm} \\ &\approx 6.2\; {\rm rpm} \end{aligned}$ .

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1 year ago

CondensationRadiationConvectionConduction transfers heat within the atmosphere and ocean.

sveta [45]

Condensation, radiation, convection, conduction are many ways heat is transferred from atmosphere to ocean. however heat comes from the sun then, to the atmosphere.

6 0

3 years ago

Read 2 more answers

NEED HELP ASAP ONLY HAVE 1 MINUTE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

matrenka [14]

My guess is Wedge & Pulley

5 0

3 years ago

NEED Answers ASAP!!!!!

Maslowich

The force on the truck is F=13650 N

Explanation:

Solving the problem

Given data,

M= 1500 kg

A= 9.1 m/s

We have the formula,

F= M×A

F= 1500 × 9.1

F=13650 N

The Force on the truck is F=13650 N

6 0

3 years ago

The magnitude of the acceleration of gravity, in the International System of Measurements, in an object that falls vertically is

Vinvika [58]

Answer:

option D

Explanation:

the correct answer is option D

acceleration of a body under free fall due to the effect of gravity is the called acceleration due to gravity.

Acceleration due to gravity is a constant value.

According to the International System of Measurements the acceleration due to gravity is 9.81 m/s² when an object falls vertically.

acceleration due to gravity is denoted by 'g'.

8 0

3 years ago

What is measurements?​

What is measurements?