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kirill115 [55]
2 years ago
5

Which is an equation in point-slope form for the given point and slope?

Mathematics
1 answer:
Kisachek [45]2 years ago
8 0

The point-slope form: y-y_1=m(x-x_1)

Q2.

(1,\ -7)\to x_1=1,\ y_1=-7\\m=1\\\\y-(-7)=1(x-1)\\\\y+7=(x-1)

Q3.

(5,\ 9)\to x_1=5,\ y_1=9\\m=2\\\\y-9=2(x-5)

Q4.

y=mx+b\\\\(0,\ 1)\to b=1\\\\y=mx+1

The formula of a slope: m=\dfrac{x_2-x_1}{y_2-y_1}

((-2,\ 4)\to x_1=-2,\ y=4\\(2,\ -2)\to x_2=2,\ y_2=-2\\\\m=\dfrac{-2-4}{2-(-2)}=\dfrac{-6}{4}=-1.5

y=-1.5x+1

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kow [346]

Answer:

<h3>           f(x) = 5x² + 2x</h3><h3>           g(x) = 6x - 6</h3>

Step-by-step explanation:

\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6

4 0
2 years ago
Mutiply (-2/3)(-1/6)
Marat540 [252]

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Step-by-step explanation:

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7 0
3 years ago
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To the nearest degree what is the measure of each exterior angle of a regular dodecagon
malfutka [58]

Answer:

30^{\circ}

Step-by-step explanation:

We are asked to find the measure of each exterior angle of a regular dodecagon.

We know that a regular dodecagon is a 12 sided regular polygon with each side equal.

We know that measure of each angle of n-sided regular polygon can be found using formula:

\text{Each exterior angle}=\frac{360^{\circ}}{n}

Upon substituting n=12 in above formula, we will get:

\text{Each exterior angle of a regular dodecagon}=\frac{360^{\circ}}{12}

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Therefore, the measure of each exterior angle of a regular dodecagon is 30 degrees.

3 0
2 years ago
Factor this polynomial. -3x^2 - 16x - 5 A. (3x + 1) (x - 5) B. (3x - 1) (x - 5) C. -1 (3x + 1) (x + 5) D. (-3x + 1) (x + 5)
Mrac [35]

Answer:

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Step-by-step explanation:

Step 1: Factor out negative

-1(3x² + 16x + 5)

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