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xenn [34]
3 years ago
14

F(x) = — 3х2 – 6х +5 maximum and minimum value

Mathematics
1 answer:
gregori [183]3 years ago
5 0

9514 1404 393

Answer:

  maximum: 8; no minimum

Step-by-step explanation:

A graph can be useful. I find a graphing calculator handy. It shows the maximum of the function is f(-1) = 8. Since the parabola goes to -∞ for large values of x, there is no minimum.

  maximum: 8

__

You can also find the maximum by putting the function in vertex form.

  -3(x^2 +2x) +5 . . . . factor the leading coefficient from the x terms

 -3(x^2 +2x +1) +5 -(-3)(1) . . . . add the square of half the x-coefficient, subtract the equivalent amount

  -3(x +1)^2 +8 . . . . . . the vertex form of the expression for f(x)

This form is ...

  a(x -h)^2 +k . . . . . with a=-3, h=-1, k=8

so the vertex is (h, k) = (-1, 8) -- the same as shown on the graph. The negative value of 'a' tells you the parabola opens downward, so the vertex is the maximum. The maximum is 8 at x = -1.

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1) We can get that number hit and trial method.

It is said that "two three-digit numbers and wrote one six-digit number, which is equal to seven times their product".

Let us check number 143.

If we write 143 two times without any sign in between , we get 143143 ( a six digit number).

But if we multiply 143 × 143 , we get 20449.

7 times of 20449 equals 143143.

<h3>Therefore, the required three digit number is 143.</h3>

2) Let us assume required prime numbers are a, b and c.

Product of a, b and c= abc.

Sum of a, b and c = a+b+c.

"Their product is five times greater than their sum."

Therefore,

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Plugging a=2 and b=5.

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10c = 35 +5c.

Subtracting 5c from both sides, we get

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Let us check by taking a=2 and b=7.

Plugging a=2 and b=7 in equation (1), we get

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c=9. But it's not a prime number.

Let us take a=2 and b=11, we get

2×11×c = 11(2+11+c).

c=13   (A prime)

If we take a=2 and b=17, we get

2×17×c = 17(2+17+c).

c=19   (A prime).

<h3>On the same way, if we continue the process, we can get many "cool" triples.</h3>


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