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gavmur [86]
3 years ago
7

An antique store increases all of its prices by $40\%$, and then announces a $25\%$-off-everything sale. What percent of the ori

ginal prices (before the increase) are the new prices?
Mathematics
2 answers:
Nostrana [21]3 years ago
6 0
Let X be the original price. 
Do a 40% increase we get the price: X+0.4X=1.4X
Doing a 25% off we get the new price:
(1.4X)-0.25(1.4X)=1.05X 
                            =X+0.05X.
The new prices are 5% increase from the original price. 

Aleks04 [339]3 years ago
3 0
The most likely solution is 105%

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Cost of milk per carton = $ 70 cents = 70/100 = $0.7
Cost of bread per loaf = $60 cents = 60/100 = $0.6
Cost of cereals per box = $50 cents = 50/100 = $0.5
Cost of meat per pound = $1.50

If x is the number of cartons of milk bought, then
Number of loafs = x/2
Number pf boxes of cereals = x/2 +1
Number of pounds of meat = x/2 +1

Therefore,
0.7*x + 0.6*x/2 + 0.5 (x/2+1) + 1.5 (x/2+1) = 10
0.7x + 0.3x + 0.25x + 0.5 + 0.75x + 1.5 = 10
2x + 2 =10
2x = 8
x = 4

Substituting;
Milk cartons = 4
Number of bread = 4/2 = 2
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A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base
Olenka [21]

Answer:

The base of triangle is  \frac{8}{\sqrt{3}} \ m and the height of triangle is  \frac{12}{\sqrt{3}} \ m.

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = x\times\frac{1}{2} =\frac{x}{2} \ m.

The height of triangle = x\times \frac{3}{4} =\frac{3x}{4}\ m.

The area of triangle = 16\ m^2.

Now, we put the formula of area to solve:

Area=\frac{1}{2} \times base\times height

16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}

16=\frac{3x^2}{16}

<em>Multiplying both sides by 16 we get:</em>

<em />256=3x^2<em />

<em>Dividing both sides by 3 we get:</em>

<em />\frac{256}{3} =x^2<em />

<em>Using square root on both sides we get:</em>

\frac{16}{\sqrt{3}}=x

x=\frac{16}{\sqrt{3}}

Now, by substituting the value of x to get the base and height:

Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.

<em>So, the base of triangle = </em>\frac{8}{\sqrt{3}} \ m.<em />

Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.

<em>Thus, the height of triangle =  </em>\frac{12}{\sqrt{3}} \ m.<em />

Therefore, the base of triangle is  \frac{8}{\sqrt{3}} \ m and the height of triangle is  \frac{12}{\sqrt{3}} \ m.

7 0
4 years ago
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