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Anestetic [448]
4 years ago
11

You can represent an odd integer with the expression 2n+1, where n is any integer. write and solve an equation to find three con

secutive odd integers that have a sum of 63.
Mathematics
1 answer:
Igoryamba4 years ago
5 0
<span>I :  2n + 1 
II : 2n + 3
III : 2n +5
(2n + 1) + (2n + 3) +(2n+5)=63
6n+9=63
n=9
I : 2n+1=9*2+1=19
II : 2n+3=9*2+3=21
III : 2n+5=9*2+5=23

19+21+23=63

</span>
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Which ratio is not equivalent to the others?
snow_lady [41]

Answer:

4:7

Step-by-step explanation:

3:5=6:10/2=3:5

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8 0
4 years ago
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3 years ago
Solve 3^n=5. How to solve n?
Ne4ueva [31]

Answer:

\huge\boxed{n=\log_35}

Step-by-step explanation:

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3 years ago
(-i)+6-(3-7i)<br>Can you also explain it to me?
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2. gather like terms ( 6 - 3 ) + ( -i + 7i )

3. simplify

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