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frez [133]
3 years ago
13

24 students and Jamall's class are wearing tennis shoes there are 30 students in his class tomorrow says that 70% of his class i

s wearing tennis shoes is Jamall correct explain your reasoning
Mathematics
1 answer:
alexdok [17]3 years ago
5 0
10% = 3
70% = 3 * 7
= 21 students

Jamall is wrong because 70% of the class = to 21 students.
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There are 220 people who voted at the 6th grade meeting.Sixty percent of the voters are in favor of changing the school mascot.H
Amiraneli [1.4K]
60% of 220 is 132.
220 -132 = 88

88 people.
4 0
3 years ago
9/15 + 7/15= ?<br><br><br><br><br> Pls help I’m being dumb :0
Mashutka [201]
I think the answer is 1.06666666667
7 0
3 years ago
Urgenttttt please I need it fast​
dolphi86 [110]

Answer:

Below in bold.

Step-by-step explanation:

c) 3 x (9^2)^3/4 x ((81^3)^5/6

= 3 x 81^3/4 x 81^15/6

= 3 x 81^(3/4 + 15/6)

= 3 x 81^13/4

= 3 x 3^13

= 3^14

= 4,782,969.

f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2

=  5^-2 x^2y^-4 / 625 x^4y^-2

=  5^-2 x^-2 y^-2 / 5^4

= 5^-6 x^-2y^-2

= 0.000064x^-2y^-2.

5 0
3 years ago
Colton and his children went into a movie theater and he bought $48.50 worth of bags of popcorn and candies. Each bag of popcorn
Inessa [10]

Answer:

5 bags of popcorn and 6 candies.

Step-by-step explanation:

(5 * $5.50) + ($3.5*6) = $48.5

4 0
3 years ago
] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was
Bad White [126]

Answer:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

\hat p=\frac{502}{1045}=0.480 estimated proportion of college graduates with a mentor

p_o=0.42 is the value that we want to test

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:p \leq 0.42  

Alternative hypothesis:p > 0.42  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

7 0
3 years ago
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