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3 years ago

What does it mean for the ratio of surface area to volume to be small or large? Which ratios are better economically?

2 answers:

8 0

I small ratio would mean it's a small difference like 60:62 would be a small ratio a big ratio might be like 2:14 do you understand how it works now?

ValentinkaMS [17]3 years ago

3 0

The goal is to get the volume as large as possible while the surface area is made as small as possible. Why? Because the volume is the amount of stuff you can hold and the surface area is the amount of material to make the container.

Consider an example of making a cup. The inside portion is the amount the cup can hold. The more liquid, the better. The cup makers want to use as little material as possible so that they reduce costs. If the cup makers produce a cup that has volume of 10 cubic inches and uses 10 square inches of material, then the surface area to volume ratio is 10:10 which reduces to 1:1. A more efficient cup is made if that same volume (10 cubic inches) can be made for less material say 5 square inches to make the ratio now 5:10 which reduces to 1:2.

So in summary, reducing the surface area to volume ratio will make more sense economically as the company makes more money while reducing costs (therefore increasing overall profit)

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It costs $3.45 to buy 3/ 4 lb of chopped walnuts. How much would it cost to purchase 7.5 lbs of walnuts?

Dmitry_Shevchenko [17]

Answer:

The cost of the 7.5 lbs of walnuts be $2.16 .

Step-by-step explanation:

As given

It costs $3.45 to buy $\frac{3}{4}$ lb of chopped walnuts.

i.e

$\$ 3.45 = \frac{3}{4}\ lb$

Now calculate the cost of one pound .

$Cost\ of\ one\ pound = \frac{3.45}{\frac{3}{4}}$

$Cost\ of\ one\ pound = \$ 0.2875$

Now calculated the cost of the 7.5 lbs of walnuts .

Cost of 7.5 lbs of walnuts = 7.5 × 0.2875

= $2.16 (Approx)

Therefore the cost of the 7.5 lbs of walnuts be $2.16 .

7 0

3 years ago

Read 2 more answers

Now, lets evaluate the same integral using power series. first, find the power series for the function f(x = \frac{32}{x^2+4}. t

BlackZzzverrR [31]

No idea what the previous part of the problem is, but you have

$f(x)=\dfrac{32}{x^2+4}=\dfrac8{1-\left(-\frac{x^2}4\right)}=\displaystyle8\sum_{n\ge0}\left(-\frac{x^2}4\right)^n$
$f(x)=\displaystyle8\sum_{n\ge0}\left(-\dfrac14\right)^nx^{2n}$

which is valid for $\left|-\dfrac{x^2}4\right|$ , or $|x|$ . So the integral from 0 to 2 is

$\displaystyle\int_0^2f(x)\,\mathrm dx=\int_0^28\sum_{n\ge0}\left(-\frac14\right)^nx^{2n}\,\mathrm dx$
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\int_0^2x^{2n}\,\mathrm dx$

Note that since the power series only converges on the interval if $x$ is strictly less than 2, which means we have to treat this as an improper integral.

$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\int_0^tx^{2n}\,\mathrm dx$ [/tex]
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\frac{x^{2n+1}}{2n+1}\bigg|_{x=0}^{x=t}$
$=\displaystyle8\sum_{n\ge0}\frac{(-1)^n}{2^{2n}(2n+1)}\lim_{t\to2^-}t^{2n+1}$
$=\displaystyle16\sum_{n\ge0}\frac{(-1)^n}{2n+1}$
$=16-\dfrac{16}3+\dfrac{16}5-\dfrac{16}7+\dfrac{16}9+\cdots$

6 0

3 years ago

You are attending a college night. There is a different school in each classroom. Of the schools in attendance 30% had a sports

elixir [45]

Answer:

0.10

Step-by-step explanation:

Technically it's 0.12 but I only say this because they rounded by from 58 to 60 in their question

7 0

2 years ago

2. Mr. Abdulla has 160 cows, goats, horses, and chickens on his farm. 19% of the animals are cows, 28% are goats, 13% are horses

siniylev [52]

Step-by-step explanation:

28 + 19 + 13 equal 60%

therefore 40% divided by 60% multiply by 160 gives number of chicks

6 0

3 years ago

Jessica wants to calculate her grade in her accounting class.she has four test grades (82, 65, 71, and 77) and a homework grade

Aleks04 [339]

To solve the problem, get the percentage of each test by multiplying the score and the percentage then add it all up:

82 * .25 (highest test grade) + 65* .15 (lowest test grade) + 71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework grade)

= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number

3 0

3 years ago