<span>We are given that ||e|| = 1, ||f|| = 1. </span>
<span>Since ||e + f|| = sqrt(3/2), we have </span>
<span>3/2 = (e + f) dot (e + f) </span>
<span>= (e dot e) + 2(e dot f) + (f dot f) </span>
<span>= ||e||^2 + 2(e dot f) + ||f||^2 </span>
<span>= 1^2 + 2(e dot f) + 1^2 </span>
<span>= 2 + 2(e dot f). </span>
<span>So e dot f = -1/4. </span>
<span>Therefore, </span>
<span>||2e - 3f||^2 = (2e - 3f) dot (2e - 3f) </span>
<span>= 4(e dot e) - 12(e dot f) + 9(f dot f) </span>
<span>= 4||e||^2 - 12(e dot f) + 9||f||^2 </span>
<span>= 4(1)^2 - 12(-1/4) + 9(1)^2 </span>
<span>= 4 + 3 + 9 </span>
<span>= 16. </span>
Answer:
see below (I hope this helps!)
Step-by-step explanation:
The range is simply all the y values of a function. Remember, a closed dot signifies ≤ or ≥ whereas an open dot signifies < or >. We see that the minimum y value is -11, and since it has a closed dot, we can write y ≥ -11. From the graph, the maximum y value is 11 and since it has an open dot, we can write y < 11, therefore, the final answer is -11 ≤ y < 11.
Add the three angles and set them to 180
4x-13+15+x+18=180
5x+20=180
5x=160
x=32
Then plug in to get A and C
A=4*32-13
A=115
C=32+18
C=50
Answer:
The length of the longer base he 35 units
Step-by-step explanation:
Here, we want to find the length of the longer base of the trapezoid
Mathematically, we can find the area using the formula;
1/2( a + b) h
where a is the shorter base
b is the longer base
h is the height
Let the shorter base be x
The other base is 5 times this length and that makes 5 * x = 5x
Height is the average of both bases;
(x + 5x)/2 = 6x/2 = 3x
Substituting these in the formula, we have ;
1/2(x + 5x)3x = 441
3x(6x) = 882
18x^2 = 882
x^2 = 882/18
x^2 = 49
x^2 = 7^2
x = 7
But the longer base is 5x and that will be 5 * 7 = 35 units
