The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
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Answer:
0/8
Step-by-step explanation: i tried my best
Answer:
X = 24
Step-by-step explanation:
Add 9 To Both Sides
X - 9 + 9 = 15 + 9
Simplify
X = 24
Best Of Luck,
- I.A. -
Answer:
your answer is (A)
Step-by-step explanation:
in the affirmative
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Answer:No its not a function
Step-by-step explanation:
