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2 years ago

Please help me out !!! please answer asap

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

8 0

Answer:

the answer is 12

Step-by-step explanation:

p(n)= 6-2(1+n)

so if p(2)

then n=2

therefore,

p(2)= 6-2(1+2)

= 4×3

=12

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In 2016, the top 1 percent of taxpayers accounted for more income taxes paid than the bottom 90 percent combined. The top 1 perc

qaws [65]

Answer:

$464Billion

Step-by-step explanation:

If 37.3%=$538B

32.2%=?

$By \ Cross \ Multiplying:-\\32.2\%=>\frac{32.2\%*538}{40\%}\\=464.440$

32.2% is roughly $464Billion in taxes

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2 years ago

What is 6.45 divided by 5

Serggg [28]

1.29 is 6.45 divided by 5

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2 years ago

Read 2 more answers

The price for a gallon of whole milk has increased from 2006 to 2008. from 2006 to 2007, the cost of whole milk increased by app

valkas [14]

You have the starting price of $1.99. To get the increased price, divide 1.99 by .56 (.56 is the decimal form of 56%). You would get $3.55. This is for the year 2007. So for 2008, divide 3.55 by .42. The answer is $8.45. You can check the answers by multiplying the answers you go the the percentage. Ex. 8.45* .42=3.55 (rounded)

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2 years ago

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali

Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

$W =$ Wednesday

$T =$ Thursday

$F =$ Friday

$S =$ Saturday

Their corresponding probabilities are

$P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1$

Since $Y$ = number of days beyond Wednesday that it takes for both magazines to arrive(so possible $Y$ values are 0, 1, 2 or 3)

The possible number of outcomes are therefore $4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)$

The values associated for each of the outcomes are as follows:

$Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3$

The probability mass function of $Y$ is,

$P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19$

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3 years ago

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jeka57 [31]

Answer:

what is the question send it in the comment fast

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2 years ago

Please help me out !!! *please answer asap*

Please help me out !!! please answer asap