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Zarrin [17]
2 years ago
12

2. The radius of a circle is 9 yards. Find the diameter.

Mathematics
1 answer:
kogti [31]2 years ago
5 0

Answer:

18

Step-by-step explanation:

9 x 2 = 18

radius x 2 = diameter

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Hello! Could you please help with these? It was due quite a long time ago. I have a D in this class and need to get my grades up
Digiron [165]

Answer:

16. y=7x

17. y=0.5x

18. y=3x

19. y=2x

Step-by-step explanation:

Equation is y=kx where k is a constant of proportionality.

16.

\frac{y}{x}=\frac{10.5}{1.5}=\frac{14}{2}=\frac{24.5}{3.5}=\frac{35}{5}=7

So, equation is y=7x

17.

\frac{y}{x}=\frac{1}{2}=\frac{2}{4}=\frac{2.5}{5}=\frac{3.5}{7}=\frac{1}{2}=0.5

Equation is y=0.5x

18.

\frac{y}{x}=\frac{6}{2}=\frac{9}{3}=\frac{15}{5}=\frac{18}{6}=3

Equation is y=3x

19.

\frac{y}{x}=\frac{4}{2}=\frac{8}{4}=\frac{14}{7}=\frac{18}{9}=2

Equation is y=2x

4 0
3 years ago
Help I have to turn this in. In a couple hours
Gelneren [198K]

28. Surface Area

This is some sort of house-like model so for every face we see there's a congruent one that's hidden.  We'll just double the area we can see.

Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )

Let's separate the area into the area of the front and the sides; the front will help us for problem 29.

Front =  [14×9 rectangle] + [triangle base 14, height 6]

          = 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft

OneSide =  2[15×9 rectangle] = 30×9 = 270 sq ft

Surface Area = 2(168 + 270) = 876 sq ft

Answer: D) 876 sq ft

29.  Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.  

Volume = 168 * 15 = 2520 cubic ft

Answer: D) 2520 cubic ft

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2 years ago
A coat that usually cost $123 is marked 1/3 off. what is the sale price of the coat
Snowcat [4.5K]
Well if it is marked 1/3 off, then you're actually paying 2/3 of it. 2/3 of 123. " of " means multiply 2/3 * 123 = 246/3 = 82 So it now costs $ 82
6 0
3 years ago
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Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.
ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region \mathcal T by computing the double integral of the density function over \mathcal T:

\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy

The boundary of \mathcal T is determined by a set of lines in the x,y plane. One way to describe the region \mathcal T is by the set of points,

\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}

So the mass is

\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx

=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx

=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52

6 0
3 years ago
What is equivalent to 4/5
choli [55]
The equivalent to 4/5 is 0.8.
6 0
3 years ago
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