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jolli1 [7]
3 years ago
8

Given: The coordinates of iscosceles trapezoid JKLM are J(-b, c), K(b,c), L(a,0), and M(-a,0).

Mathematics
2 answers:
Vanyuwa [196]3 years ago
7 0

Answer with explanation:

It is given that, coordinates of Isosceles trapezoid J K L M are J(-b, c), K(b,c), L(a,0), and M(-a,0).

To Prove: The diagonals of an isosceles trapezoid are congruent.

Proof:

  Distance formula , that is distance between two points in x y plane is given by

       =\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Where, (x_{1},y_{1}),(x_{2},y_{2})} are coordinates of two points in the plane.

Length of Diagonal J L

                  =\sqrt{(a+b)^2+(0-c)^2}\\\\=\sqrt{(a+b)^2+c^2}

Length of Diagonal K M

           =\sqrt{(a+b)^2+(0-c)^2}\\\\=\sqrt{(a+b)^2+c^2}

So, we can see that,

  J L = KM  =\sqrt{(a+b)^2+(c)^2}

Hence,The diagonals of an isosceles trapezoid are congruent.

So ,

  KM=\sqrt{(a+b)^2+c^2}

Option C

Anuta_ua [19.1K]3 years ago
4 0
The answer for this question is B. Let me know
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100 grams/day of substance x is filtered, 50 grams/day is reabsorbed, 75 grams/day is secreted and 125 grams/day is excreted. su
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100 grams/day of substance x is filtered, 50 grams/day is reabsorbed, 75 grams/day is secreted and 125 grams/day is excreted. substance x is undergoing in the nephron net secretion and would have a clearance value that is greater than GFR

The formula for calculating clearance is Cx is given in terms of volume per time, where Ax is the quantity of x removed from the plasma, Px is the average plasma concentration, and Cx = Ax /Px.

Ax= 125 grams/day

and Px= 50 grams/day

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Therefore, the creatinine clearance overestimates GFR more severely in patients with a very low GFR than in those with higher GFR values. For a patient with a very low GFR, the secreted component is a relatively larger fraction of the total amount excreted.

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Complete question :

Patient was experiencing respiratory acidosis (the increased hydrogen ion concentration was predominantly activating his peripheral chemoreceptors). 100 grams/day of substance X is filtered, 50 grams/day is reabsorbed, 75 grams/day is secreted and 125 grams/day is excreted. Substance X is undergoing ___________ in the nephron and would have a clearance value that is _________.(choose one)

A)net reabsorption, less than GFR

B)net secretion, greater than GFR

C)neither net reabsorption nor net secretion, equal to GFR

D)net reabsorption, greater than GFR

E) net secretion, less than GFR

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