How do I find the domain n range of this graph
1 answer:
Domain = {-3, 2}
Range = All real numbers
We can represent the range in interval notation as which is basically saying
. The range is all real numbers due to the arrows meaning the graph extends up and down forever. So any y value is possible.
Notice with the domain we only have 2 valid x values -3 and 2. No other x values are allowed. Normally we use an interval of some kind to set up the domain, but we only have a set of values instead. The curly braces indicate "set".
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Answer:
The degrees of freedom are given by:
The p value would be given by:
Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60
Step-by-step explanation:
Information given
60, 56, 60, 55, 70, 55, 60, and 55.
We can calculate the mean and deviation with these formulas:
Replacing we got:
represent the mean
represent the sample standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level
t would represent the statistic
represent the p value
Hypothesis to test
We want to test if the true mean is less than 60, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic would be given by:
(1)
Replacing the info we got:
The degrees of freedom are given by:
The p value would be given by:
Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60
Answer:
a). 0.294
b) 0.11
Step-by-step explanation:
From the given information:
the probability of the low risk = 0.60
the probability of the high risk = 0.40
let represent no claim
let represent 1 claim
let represent 2 claim :
For low risk;
so, = (0.80 * 0.60 = 0.48),
= (0.15* 0.60=0.09),
= (0.05 * 0.60=0.03)
For high risk:
= (0.50 * 0.40 = 0.2),
= (0.30 * 0.40 = 0.12) ,
= ( 0.20 * 0.40 = 0.08)
Therefore:
a), the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:
b) What is the probability that a randomly selected policyholder filed two claims?
the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08
= 0.11