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3 years ago

13

Classify the pair of angles

2 answers:

DochEvi [55]3 years ago

5 0

Adjacent angles are angles that share a vertex and a side; these angles do not.
Complementary angles are angles that add to equal 90 degrees; these angles do not.
Supplementary angles are angles that add to equal 180 degrees; these angles do not.

Answer:
D. None of these.

never [62]3 years ago

4 0

The answer TO THE QUESTION IS D

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.Solve 5x – 3y = 9 for y

german

Move variable to right -
-3Y=9-5x
Divide both sides by -3 -
y=-3+5 over 3 x 5/3 x(not right besides the 3 it is on the end)

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3 years ago

Write the vector v in the form aiplusbj, given its magnitude left norm Bold v right norm and the angle alpha it makes with the

photoshop1234 [79]

Answer:

$6\sqrt{3}i-6j$

Step-by-step explanation:

Given:

The magnitude, v=12

The angle $\alpha$ it makes with the positive x-axis = $150^0$

Now for a vector (x,y)

$\alpha =tan^{-1}(\frac{y}{x} )$ ; and

$v=\sqrt{x^2+y^2}$

Therefore:

$150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}$

$y=-\frac{x \sqrt{3}}{3}$

Similarly:

$v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2$

$144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}$

Recall that:

$y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3} \sqrt{3}}{3}=-6$

Therefore: $(x,y)=(6\sqrt{3}, -6)$

The vector in the form ai+bj is therefore:

$6\sqrt{3}i-6j$

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What’s the difference between numbers that are to the power of with parentheses and no parentheses. For example (-2/5)^3 and -2/

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Answer:

See below

Step-by-step explanation:

The first one 'cubes' the denominator AND the numerator:

(-2/5)^3 = -2/5 * -2/5 * -2/5 = -8/125

The second one 'cubes' only the denominator:

-2/5^3 = -2 / (5 * 5 * 5) = - 2 / 125

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Answer:

Where's the equation?

Step-by-step explanation:

Where's the equation?

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Marizza181 [45]

Answer:

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Step-by-step explanation:

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