From the figure, we can conclude that the little triangle is an isosceles triangle, the greatest angle is 90 because ∠A = 90 and they are supplementary, therefore, using the triangle sum theorem:

$\begin{gathered} m\angle J=m\angle K \\ m\angle K+m\angle K+90=180 \\ 2m\angle K=180-90 \\ 2m\angle K=90 \\ m\angle K=\frac{90}{2} \\ m\angle K=45 \end{gathered}$

8 0

11 months ago

Factor completely x2 + 20x + 99

Bad White [126]

$x^2 + 20x + 99=x^2+9x+11x+99=x(x+9)+11(x+9)=(x+11)(x+9)$

6 0

2 years ago

I need help finding the reference angles for these angles.

Salsk061 [2.6K]

Convert the angles to degrees. Remember there are 2pi radians in a circle, and a circle has 360 degrees, so conversion factor is 180degrees/pi. Then you can easily approximate the reference angle. Remember you make the reference angle from the positive x-axis and the reference angle will be the angle between the terminal side and the nearest x-axis (either positive side or negative side of the x-axis).
1) $1.4 * \frac{180degrees}{pi} = 80.214 degrees$
2) $-1.4 \pi * \frac{180degrees}{ \pi } = -252 degrees$

4 0

2 years ago

Please help me on these questions and explain it thanks

Korolek [52]

ABC = 180-120=60
ACB = 180-(40+60)=80
Therefore ECD= 80 as ACB and ECD are vertically opposite angles

the solution is A as that is where the graphs intersect each other

6 0

3 years ago