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umka21 [38]
3 years ago
10

Suppose you have an empty jar with a mass of 196.0 g. After filling the jar with jelly beans the mass of the jar + jelly beans i

s 323.8 g. If the average mass of a Jelly bean is 1.23 grams, estimate how many Jelly beans were added to the jar.
Mathematics
1 answer:
garik1379 [7]3 years ago
4 0

Answer: About 104 jelly beans were added to the jar.

Step by Step Explanation: If you subtract the mass of the jar from the mass before you added jelly beans you will get 127.8. Once you divide that number by 1.23 you will get about 104.

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3 includes of snow in 5 hours?
lbvjy [14]

Answer:

3 TIMES 5

Step-by-step explanation:

7 0
3 years ago
Elise and her dad are planning to attend the state fair. An adult ticket is $21.00. The price of an adult ticket is $10.00 more
solong [7]

Answer:

C. two thirds x + 10 = 21

Step-by-step explanation:

Given

Price of adult ticket = $21.00

Let x be the price of student ticket

Then

two third of the student ticket will be:

\frac{2}{3} x

The statement $10.00 more than two third of student ticket:

\frac{2}{3} x+10

As we are given in the question that the adult ticket price is $21.00 and the second explanation is th equation formed by the given statement

So, both will be equivalent

\frac{2}{3} x+10 = 21

Solving this equation for x will give us the price for the student ticket.

Hence,

C. two thirdsx + 10 = 21 is the correct answer ..

3 0
3 years ago
License plates are made using 3 letters followed by 2 digits. How many plates can be made if repetition of letters and digits is
Helga [31]

Answer:

26^3\times10^2 = 1757600

option B is correct

Step-by-step explanation:

We have 5 spaces in the license plate:

_ _ _ _ _

we have 26 available letters, and 10 available numbers.

starting with letters:

  • how many choices do i have to place the 1st letter? 26.

26 _ _ _ _

  • how many choices do i have to place the 2nd letter? 26 (since we're allowed to repeat letters)

26 26 _ _ _

  • how many choices do i have to place the 3rd letter? 26

26 26 26 _ _

we've used all the places for letters, (note: the exact position of the letters doesn't matter here, the first letter could've been placed anywhere in _ _ _ _ _, but the amount of possible choices for letters would always be 26).

let's move on to numbers.

  • how many choices do i have to place the 1st number? 10

26 26 26 10 _

  • how many choices do i have to place the 2nd number? 10

26 26 26 10 10

we've completed our number plate. Next we'll simply multiply all these numbers to get all the possible arrangements in which numbers and letters can be displayed on a license place.

26^3\times10^2 = 1757600

option B is correct

8 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
fenix001 [56]

Answer:

2, 7, 114

Step-by-step explanation:

(3 + 0.5x)(38 - 4x)

114 + 19x - 12x - 2x²

-2x² + 7x + 114

7 0
3 years ago
If g=77cm and h=85cm what is the length of f
umka2103 [35]
The first thing you need to do is add and then subtract
5 0
3 years ago
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