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3 years ago

5

To make a greeting card Bryce used 1/8 sheet of red paper,3/8 sheet of green paper and 7/8 sheet of white paper. How much paper

did Bryce use

1 answer:

Flura [38]3 years ago

4 0

Rounding the answer would be 2 sheets of paper, but the exact answer would be 1 full sheet and 3/8 of a sheet.

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A figure is made of 2 rectangular prisms...<br> what is the volume?

MaRussiya [10]

The volume of the figure that is composed of two rectangular prisms is: 146 cubic in.

<h3>What is the Volume of a Rectangular Prism?</h3>

The volume of a rectangular prism = (length)(width)(height).

The figure can be decomposed into two rectangular prisms. Find the volume of each of the prisms.

Volume of rectangular prism 1:

Length of the prism = 8 in.

Width of the prism = 7 in.

Height of the prism = 1 in.

Volume of rectangular prism 1 = (8)(7)(1) = 56 in.³

Volume of rectangular prism 2:

Length of the prism = 10 in.

Width of the prism = 9 in.

Height of the prism = 1 in.

Volume of rectangular prism 1 = (10)(9)(1) = 90 in.³

Volume of the figure = 90 + 56 = 146 cubic in.

Learn more about volume of rectangular prism on:

brainly.com/question/12917973

#SPJ1

7 0

1 year ago

In a random sample of 1066 U.S. adults, 580 think that the U.S. government

alexandr402 [8]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the adults who think that the U.S. government is doing too little to protect the environment presently and the adults who think that the U.S. government is doing too little to protect the environment 10 years ago. The population proportions would be p1 and p2 respectively.

p1 - p2 = difference in the proportion of adults who think that the U.S. government is doing too little to protect the environment presently and the adults who think that the U.S. government is doing too little to protect the environment 10 years ago.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success

n represents number of samples

For the present,

x1 = 580

n1 = 1066

p1 = 580/1066 = 0.54

For 10 years ago,

x2 = 514

n2 = 1038

P2 = 514/1038 = 0.5

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (580 + 514)/(1066 + 1038) = 0.52

1 - pc = 1 - 0.52 = 0.48

z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.54 - 0.5)/√(0.52)(0.48)(1/1066 + 1/1038) = 0.04/0.02178551744

z = 1.84

Since it is a two tailed test, the curve is symmetrical. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area above the test z score in the right tail 1 - 0.967 = 0.033

We would double this area to include the area in the left tail of z = - 1.84 Thus

p = 0.033 × 2 = 0.066

Alpha = 0.1

Since alpha, 0.1 > p value 0.066, we would reject the null hypothesis.

Therefore, at a = 0.10, we can reject the

claim that the proportion of U.S. adults who think that the U.S. government

is doing too little to protect the environment has not changed.

4 0

3 years ago

A student answers a multiple-choice examination question that offers four possible answers. Suppose the probability that the stu

Salsk061 [2.6K]

Answer:

The value is $P(A | W) = 0.941$

Step-by-step explanation:

From the question we are told that

The probability that the student knows the answer to the question is $P(A) = 0.8$

The probability that that the student will guess is $P(G) = 0.2$

The probability that that the student get the correct answer given that the student guessed is $P(W /G) = 0.25$

Here W denotes that the student gets the correct answer

Generally it a certain fact that if the student knows the answer he would get it correctly

So the probability the the student got answer given that he knows it is

$P(W | A) = 1$

Generally from Bayes theorem we can mathematically evaluate the probability that the student knows the answer given that he got it correctly as follows

$P(A | W) = \frac{ P(A) * P(W | A )}{ P(A) * P(W | A) + P(G) * P(W| G)}$

=> $P(A | W) = \frac{ 0.8 * 1}{ 0.8 * 1+ 0.2 * 0.25}$

=> $P(A | W) = 0.941$

4 0

3 years ago

Solve for x.<br><br> 12(x−360)=120 <br><br> Enter your answer in the box.

kenny6666 [7]

12x-4320=120
12x=120+4320
12x=4440
x=370

6 0

3 years ago

Read 2 more answers

An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de

Lelechka [254]

Answer:

(a) $P(X=10) = 0.2070$

(b) $P(X\geq 10) = 0.3798$

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

So

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

$N = 50\\m = 30\\n = 15\\X = 10$

Then:

$P (X = 10) = \frac{\frac{30!}{10!(30-10)!}\frac{20!}{5!(20-5)!}}{\frac{50!}{15!(50-15)!}}\\\\\\P(X=10) = 0.2070$

(b)

For part (b) we have:

$P(X\geq10) = 1-P(X$

$P(X\geq 10) = 1-0.6202 \\\\P(X\geq 10) = 0.3798$

4 0

3 years ago