9514 1404 393
Answer:
9(x +y)
Step-by-step explanation:
You observe that both terms have a coefficient of 9. The distributive property lets you factor that out, so you can rewrite the expression as ...
9x +9y = 9(x +y)
_____
It might help to think of parentheses as a "bag." The expression 9(x+y) tells you the contents of one bag is (x+y) and you have 9 of them. You could think of x, and y as representing two different physical objects, for example, perhaps a ball and a cube.
The first expression, 9x +9y, tells you that you have 9 of each of these objects. The distributive property says this could be the result of dumping the contents of 9 bags, each containing one each of the objects. The expression 9(x+y) is the version of the expression that shows these objects as being grouped into 9 bags.
Answer:
x = - 1
Step-by-step explanation:
(8x + 12) = 3 ( multiply both sides by 4 to clear the fraction )
3(8x + 12) = 12 ( divide both sides by 3 )
8x + 12 = 4 ( subtract 12 from both sides )
8x = - 8 ( divide both sides by 8 )
x = - 1
Answer:
4x^2+11x+23 r53
Step-by-step explanation:
4x^3-3x^2+x+7 / x-2
2 | 4 -3 1 7
8 22 46
___________
4 11 23 53
This means 4x^2+11x+23 with a remainder of 53
Answer:
A. milliliters B. 8 fluid ounces
Step-by-step explanation:
An eyedropper is very small and can only hold a small amount. You can eliminate 2 from the start: millimeter and meter. These two are use for measuring distance not volume. ex.) I walked 2 meters. A liter is too big for an eyedropper. ex.) 1 liter of soda.
A glass full of juice would be 8 fuild ounces because a glass is basically a cup. A 8 gallons is too big, and a 8 tablespoons is too small. ex.) gallon of milk and tablespoon of sugar. 8 cups is too big because a glass is about 1 cup. 8 fluid ounces = 1 cup
Step-by-step explanation:
I've posted solutions in the picture. Rather the ways to solve them. Check and find answers on your own.
Also, I've not solved the problem by differential calculus. You can, obviously, if you're interested. Use it for ease and for tougher equations.
