I think.
2 over
3a3 + 3a2 - 3
Answer:
177 hope this helps
791 since it has no decimal places
The linear equation:
y = k x + b
We will use first two values and solve the system of equations:
11 = k * 7 + b / *(-1)
13 = k * 8 + b
---------------------
-11 = - k * 7 - b
13 = k * 8 + b
----------------------
2 = k
13 = 16 + b
b = 13 - 16 = -3
y = 2 x - 3 ( y varies directly with x )
From the Figure :
Point A is (-3 , -3)
Point B is (6 , 6)
We know that, The Mid Point of Two Points (x₁ , y₁) and (x₂ , y₂) is given by :
![\mathsf{\implies [(\frac{x_1 + x_2}{2})\;,\;(\frac{y_1 + y_2}{2})]}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cimplies%20%5B%28%5Cfrac%7Bx_1%20%2B%20x_2%7D%7B2%7D%29%5C%3B%2C%5C%3B%28%5Cfrac%7By_1%20%2B%20y_2%7D%7B2%7D%29%5D%7D)
![\mathsf{\implies Midpoint\;of\;Line\;AB\;is\;[(\frac{-3 + 6}{2})\;,\;(\frac{-3 + 6}{2})]}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cimplies%20Midpoint%5C%3Bof%5C%3BLine%5C%3BAB%5C%3Bis%5C%3B%5B%28%5Cfrac%7B-3%20%2B%206%7D%7B2%7D%29%5C%3B%2C%5C%3B%28%5Cfrac%7B-3%20%2B%206%7D%7B2%7D%29%5D%7D)
![\mathsf{\implies Midpoint\;of\;Line\;AB\;is\;[(\frac{3}{2})\;,\;(\frac{3}{2})]}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cimplies%20Midpoint%5C%3Bof%5C%3BLine%5C%3BAB%5C%3Bis%5C%3B%5B%28%5Cfrac%7B3%7D%7B2%7D%29%5C%3B%2C%5C%3B%28%5Cfrac%7B3%7D%7B2%7D%29%5D%7D)
