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3 years ago

A group of preschoolers has 63 boy and 27 girls. What is the relationship of boys to all children?

Mathematics

1 answer:

dlinn [17]3 years ago

6 0

63+27 = 90 total children

boys to all children ratio

63:90

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PLEASE HELP ME! I really need help y'all...

ikadub [295]

just a quick clarification, tis usually -4.9 and that's a rounded number to reflect earth's gravity on an object in motion, but -5 is close enough :)

$\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill$

8 0

4 years ago

Read 2 more answers

Solve for x. PLS HELP

Pavlova-9 [17]

Answer:

Its x = 3.53

Step-by-step explanation:

x= −3.5 (x + 5.73) = −32.41 = x = 3.53

hope this helped!

5 0

2 years ago

Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each goi

Viktor [21]

Answer:

The expected cost is $8.75

Step-by-step explanation:

Given

$Time = \{1pm, 2pm, 3pm, 4pm\}$

$C_1 = \$5$ --- If Bob and Anna meet

$C_2 = \$10$ --- If Bob and Anna do not meet

Required

The expected cost of Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

$(Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)$ $,(3,4),(4,1),(4,2),(4,3),(4,4)\}$

$n(Bob, Anna) = 16$

The outcome of them meeting at the same time is:

$Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}$

$n(Same\ Time) = 4$

The probability of them meeting at the same time is:

$Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}$

$Pr(Same\ Time) = \frac{4}{16}$

$Pr(Same\ Time) = \frac{1}{4}$

The outcome of them not meeting:

$Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)$

$,(3,4),(4,1),(4,2),(4,3)\}$

$n(Different) = 12$

The probability of them meeting at the same time is:

$Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}$

$Pr(Different) = \frac{12}{16}$

$Pr(Different) = \frac{3}{4}$

The expected cost is then calculated as:

$Expected = C_1 * P(Same) + C_2 * P(Different)$

$Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}$

$Expected = \frac{\$5}{4} + \frac{\$30}{4}$

Take LCM

$Expected = \frac{\$5+\$30}{4}$

$Expected = \frac{\$35}{4}$

$Expected = \$8.75$

<em>The expected cost is $8.75</em>

4 0

3 years ago

How you express the average of five quizzes is 85 in mathematical expression

zvonat [6]

Let x1, x2, x3, x4, x5 be the scores for the five tests respectively and y be the average score of those tests.

y = (x1 + x2 + x3 + x4 + x5) / 5

since y = 85:

(x1 + x2 + x3 + x4 + x5) / 5 = 85

4 0

3 years ago

What are the coordinates of the image of L for a dilation with center (0, 0) and scale factor ?

miv72 [106K]

Answer:

The vertices of ABCD:

A ( - 3, 1 )

B ( 4 , - 3 )

C ( 1, 3 )

D ( - 1 , 4 )

∴ ( 4 x, 4 y ):

A ` ( - 12, 4 )

B ` ( 16, - 12 )

C ` ( 4, 12 )

D ` ( - 4 , 16 )

Step-by-step explanation: I hope this helps! ™(*/ω＼*)

5 0

3 years ago