3 years ago

Wich distance .easure 7 units

Mathematics

1 answer:

Charra [1.4K]3 years ago

8 0

Normally feet, I don't really understand your question

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BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

8 0

2 years ago

Please answer the 2 question <br> l will mark as brainiest

N76 [4]

Answer:

1. A=πr2=π·4.62≈66.4761

A≈66.48

2. A=πr2=π·22≈12.56637

A≈12.57

please mark as brainiest

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2 years ago

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The company sold four more than three times as many cars this month compared to last month. If 37 were sold this month, how many

belka [17]

11 were sold last month

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3 years ago

Ax over b plus cx over d equals e <br> solve for x

Lorico [155]

$\frac{ax}{b}+\frac{x}{d}=e\ \ \ \ \ \ |multiply\ both\ sides\ by\ "bd"\\\\bd\times\frac{ax}{b}+bd\times\frac{cx}{d}=bde\\\\adx+bcx=bde\\\\(ad+bc)x=bde\ \ \ \ \ |divide\ both\ sides\ by\ (ad+bc)\\\\\boxed{x=\frac{bde}{ad+bc}}$

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3 years ago

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT!

Natali5045456 [20]

The correct answer would be 6

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3 years ago

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