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3 years ago

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robert buys a car for $8000. at the end of each year the value of the car has decreased by 10% of its value at the beginning of

that year. calculate the value of the car at the end of 7 years.

1 answer:

kiruha [24]3 years ago

3 0

So I believe you will have to do 10% x 7 as it has been seven years which will be 70% and 70% of 8000 is 5600 so the answer will be £5600

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2+2x=45<br><br> Solve for x<br><br> 10 pts

Volgvan

2+2x=45

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0+2x = 43

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0+x=41

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2 years ago

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m_a_m_a [10]

Answer:

(0,0)

Step-by-step explanation:

The coordinates of C now are (-7,-5).

Moving C -3 on the x-axis will move -7 - 3 = -10. C is now located on (-10,-5).

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2 years ago

2.35is equivalent too

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3 years ago

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Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

<h2>DNE</h2>

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

<em>Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE</em>

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3 years ago

Please help!!!! Consider the region shaded in yellow. Which inequality does the shaded region correspond to?

denis-greek [22]

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according to the graph (0,1) and (-1,0) lies on the doted line,

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1 year ago