Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
Answer:
Opposite angles in a parrellelogram are
congruent.
Answer: hello your question lacks some data hence I will be making an assumption to help resolve the problem within the scope of the question
answer:
≈ 95 units ( output level )
Step-by-step explanation:
Given data :
P = 2000 - Q/10
TC = 2Q^2 + 10Q + 200 ( assumed value )
<u>The output level where a purely monopolistic market will maximize profit</u>
<u>at MR = MC </u>
P = 2000 - Q/10 ------ ( 1 )
PQ = 2000Q - Q^2 / 10 ( aka TR )
MR = d (TR ) / dQ = 2000 - 2Q/10 = 2000 - Q/5
TC = 2Q^2 + 10Q + 200 ---- ( 2 )
MC = d (TC) / dQ = 4Q + 10
equating MR = MC
2000 - Q/5 = 4Q + 10
2000 - 10 = 4Q + Q/5
1990 = 20Q + Q
∴ Q = 1990 / 21 = 94.76 ≈ 95 units ( output level )
Answer:
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Step-by-step explanation: