First find slope or rate of winston(0,-100) and (3,-16)
slope=(y2-y1)/(x2-x1)
slope=(-16-(-100))/(3-0)=(-16+100)/(3)=84/3=28/1
wane slope or elevation gain
y=mx+b
m=slope or rate of elevaion gain
b=yintercept or starting oint
y=30x-105
slope or rate of change is 30
30 vs 28
wane acends faster than winston
also, the starting point or when x=0 point is the starting point
wane: -105 is start
winston: -100 is start
wane started deeper
so the true statements are
Wayne ascends at a faster speeds
Wayne was deeper when he began ascending
Answer:1/13
Step-by-step explanation:
Answer:
Step-by-step explanation:
all correct
Complete question :
According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Suppose data for the sale of 39 randomly selected homes sold in Greene County, Ohio, in 2017 showed a sample mean of 3.6 weeks with a sample standard deviation of 2 weeks. Conduct a hypothesis test to determine whether the number of weeks until a house sold in Greene County differed from the national average in 2017. Useα = 0.05for the level of significance, and state your conclusion
Answer:
H0 : μ = 3
H1 : μ ≠ 3
Test statistic = 1.897
Pvalue = 0.0653
fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Step-by-step explanation:
Given :
Sample size, n = 40
Sample mean, x = 3.6
Population mean, μ = 3
Standard deviation, s = 2
The hypothesis :
H0 : μ = 3
H1 : μ ≠ 3
The test statistic :
(xbar - μ) ÷ (s/√n)
(3.6 - 3) / (2/√40)
0.6 / 0.3162277
Test statistic = 1.897
Using T test, we can obtain the Pvalue from the Test statistic value obtained :
df = n - 1; 40 - 1 = 39
Pvalue(1.897, 39) = 0.0653
Decison region :
If Pvalue ≤ α ; Reject the null, if otherwise fail to reject the Null.
α = 0.05
Pvalue > α ; We fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.
Answer:
5^6
Step-by-step explanation:
5^5×5 = 5^5×5^1 = 5^(5+1) = 5^6
_____
This may become more obvious if you remember that an exponent signifies repeated multiplication:
(5^5)·(5) = (5·5·5·5·5)·(5) = 5·5·5·5·5·5 = 5^6
