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Keith_Richards [23]
3 years ago
9

Which number is greater or equal or less than​

Mathematics
1 answer:
Anna71 [15]3 years ago
3 0
We need more to answer the question I think
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If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)
svp [43]

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

70 = 43 + n(B-A)

n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

4 0
3 years ago
Carol ate 25% of the candies in the bag. If Carol ate 24 candies, how many candies were there total in the bag?
Otrada [13]

Answer:

6

Step-by-step explanation:

100/4 = 25%

24/4 = 6

5 0
3 years ago
Flying to Kampala with a tailwind a plane averaged 158 km/h. on the return trip the plane only averaged 112km/h while flying bac
never [62]
<span>flying to kampala with a tailwind a plane averaged 158 km/h. on the return trip the plane only averaged 112 km/h while flying back into the same wind. find the speed of the wind and the speed of the plane instill air. -------------------------------- Let plane speed be "p". Let wind speed be "w". --------- Equations: p + w = 158 p - w = ...</span><span>
</span>
4 0
3 years ago
Graph the line that has a slope of 8 and includes the point (0,2).
Marrrta [24]
Graph the point (0,2). From there go up 8 points and right 1 point. Again, from the point (0,2) go down 8 points and left 1 point. Hope this helps!
4 0
2 years ago
Batteries produced by a manufacturing company have had a life expectancy of 135 hours. Because of an improved production process
Nikolay [14]

Answer:  c. z = 1.35; Reject the null hypothesis

Step-by-step explanation:

Let \mu be the average life expectancy of its batteries.

As per given , we have

Null hypothesis : H_0 : \mu =135

Alternative hypothesis : H_a : \mu >135

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Test statistic : \dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overlien{x}= sample mean

\mu= Population mean

\sigma=population standard deviation

For n=42,\ \overline{x}=140\ \&\ \sigma=24, we have

z=\dfrac{140-135}{\dfrac{24}{\sqrt{42}}}=1.35015431217\approx1.35

Critical one-tailed test value for 0.10 significance level :

z_{0.1}=1.28

 Decision : Since critical z value (1.28) < test statistic (1.35), so we reject the null hypothesis .

[When critical value is less than the test statistic value , we reject the null hypothesis .]

5 0
3 years ago
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