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4 years ago

Which number is greater or equal or less than

Mathematics

1 answer:

Anna71 [15]4 years ago

3 0

We need more to answer the question I think

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Does any one understand these questions explain if you can.

maw [93]

1) 136 is the circumference of a circle with what area? we know C=πd.
136=πd
136/π=d
d=43.290 so the radius is half that, or
r=21.645
taking area as our measure of size,
A=πr²
A=π•21.645²
A=1471.855. answer C is closest. difference is in how they and I rounded

2) c, e, and f

3 0

3 years ago

Please help I need the answer ASAP!

stepladder [879]

Answer:

the second answer choice x greater than or equal to -6

Step-by-step explanation:

because u have to find the where the equation is defined. the range is the set of values that correspond to the domain.

6 0

3 years ago

Given a line passes through point (5,8) and the origin, find the equation of the line.<br> y=

SOVA2 [1]

Answer:

y = 8/5x

Step-by-step explanation:

I'm assuming that they're asking for the equation in point-slope form.

The formula is y=mx+b where:

m = slope

b = y intercept

However, the y intercept is just (0,0) so b = 0

To find the slope we already have 2 given points: (0,0) and (5,8)

To find slope you do rise/run and you get 8/5

Substitute the slope & y intercept in the formula:

y = 8/5x

Let me know if I'm wrong!!

6 0

3 years ago

Read 2 more answers

The cost of making a cheese cake is RM45. In

mars1129 [50]

Answer:

CHEESE

Step-by-step explanation:

SKDMALSD

3 0

3 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

3 years ago

Which number is greater or equal or less than​

Which number is greater or equal or less than