Question

Solve this linear equation. Show all workings

Answer 1

$~~~~~~3x^2 +2x -1 = 0\\\\\implies 3x^2 +3x -x -1 = 0\\\\\implies 3x(x+1) - (x+1)=0\\\\\implies (x+1)(3x-1) = 0\\\\\implies x = -1,~~ x = \dfrac 13$

Answer 2

Step-by-step explanation:

3x²-3x+x-1=0

3x(x - 1) + 1(x - 1) = 0

(x - 1)(3x + 1) = 0

Either x - 1- = 0, then x = 1

or 3x + 1 = 0, then x = -1 3

x = 1 or -1 3