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Ronch [10]
3 years ago
11

Sarah Simpson is insured for bodily injury in the amount of 10/20. She is at fault in an accident in which Fred Vail ns injured.

Also injured in the accident is a pedestrian, Arthur Abel. Arthur's medical expenses total $16,000, Fred's come to $8,000. How much will the insurance pay?
Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0

Answer:

The insurance company will pay a maximum of $20,000.

Step-by-step explanation:

10/20 represent the highest monetary amount that Sarah's insurance company will pay if someone is injured.

Now, here 2 persons are injured but the top limit is $20,000, so the insurance company will pay $20,000 only.

Arthur's medical expenses total $16,000, Fred's come to $8,000. Totaling to $24,000 but the limit is $20,000.

So, $4000 will be paid by Sarah and $20,000 by the insurance company.

stepladder [879]3 years ago
4 0
The fraction 10/20 = 0.50 or 50%.

Steps:

1. Add 16,000 + 8,000

2. Multiply the total by 0.50 to find the amount that the insurance company must pay.
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7. Sky Castle Company is conducting research on 3 independent communities of 12 members each to see how they have been consuming
tresset_1 [31]

Answer:

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

Step-by-step explanation:

To solve this question, we need to use two separate binomial trials.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of at least 11 members being categorized as low risk participants.

12 members in the sample, so n = 12

30% chance to be categorized as high risk participants. So 100-30 = 70% probability of being categorized as low risk participants. So p = 0.7

This probability is

P(X \leq 11) = P(X = 11) + P(X = 12)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{12,11}.(0.7)^{11}.(0.3)^{1} = 0.0712

P(X = 2) = C_{12,12}.(0.7)^{12}.(0.3)^{0} = 0.0138

P(X \leq 11) = P(X = 11) + P(X = 12) = 0.0712 + 0.0138 = 0.0850

What is the probability that at least 11 members are categorized as low risk participants in two of three communities?

For each community, 8.50% probability of at least 11 members being categorized as low risk. So p = 0.085

Three comunities, so n = 3

This probability is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.085)^{2}.(0.915)^{1} = 0.0198

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

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3 years ago
Express sin S as a fraction in simplest terms. R S​
enyata [817]

Answer:

\sf Sin \ S = \dfrac{2}{9}

Step-by-step explanation:

<h3>Trigonometry ratios:</h3>

 \sf \boxed{\bf Sin \ S = \dfrac{opposite \ side \ of \ \angle S}{hypotenuse}}

             \sf = \dfrac{RQ}{SQ}\\\\= \dfrac{2}{9}

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