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insens350 [35]
3 years ago
14

Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.

Mathematics
1 answer:
o-na [289]3 years ago
3 0
Use the pythagorean theorem,
a^2+b^2=c^2
1^2+1^2=c^2
1+1=c^2
2=c^2
2=2
Square root of 2 is 1.41 (approximately)
c=1.41
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6-4(2x-3)+10x<br> Show and explain work
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Step-by-step explanation:

6-4(2x-3)+10x

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Monica [59]
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What is the solution to the system of equations below?
Vanyuwa [196]

Answer:

A. (–8, 2)

Step-by-step explanation:

(1)       y =  ½x + 6  

(2)       y = -¾x –  4     Set (1) = (2)  

½x +   6 = -¾x –  4     Multiply each side by 4

2x  + 24 = -3x – 16     Add 16 to each side

2x  + 40 = -3x              Subtract 2x from each side  

        40 = -5x              Divide each side by -5

(3)       x = -8                 Substitute (2) into (1)

          y = ½(-8)  +6

             = -4 + 6

             =  2

The solution to the system of equations is (-8 ,2).

You can see the graphs of the two functions in the figure below. The two lines intersect at (-8, 2).

Check:

2 = ½(-8) + 6     2 = -¾(-8) - 4

2 = -4 +6           2 = 6 - 4

2 = 2                 2 = 2

8 0
3 years ago
In the figure above, what is the area of triangle QRS?
Vlad [161]

Answer:

D) 20.

Step-by-step explanation:

First find the value of x using Pythagoras theorem:

10^2 = x^2 + (2x)^2

5x^2 = 100

x^2 = 20

x = √20

  = 2√5.

So the area of triangle

= 1/2 * base * height

= 1/2 * 2x * x

=  x^2

=  (2√5)^2

=  20.

6 0
1 year ago
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