let t = time (hrs) that they are 50 mi apart
Use pythag here; a^2 + b^2 = c^2; dist = speed * time
(30t)^2 (40t)^2 = 50^2
900t^2 + 1600t^2 = 2500
It's obvious that t = 1 hr
Answer:
part A: expression 1: 6(8m+2)
expression 2: 6m+12+42m
Part B: 6(m+2+7m)= 6(8m+2)
combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)
6(8m+2)= 6(8m+2)
Part C: 6m+12+42m=6(m+2+7m)
m=0
6(0+2+7(0))=6(0)+12+42(0)
6(2)= 12
12=12
If you subtract Betty's time for the swim, 27.948 seconds, from Nancy's time, 28.004 seconds, you will find that Betty was faster than Nancy by 0.056 seconds. She would be considered the winner of the 50-meter freestyle swim.
