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vitfil [10]
3 years ago
6

Which set of values could be from a direct proportion

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

"A"

Step-by-step explanation:

I got it correct

mr Goodwill [35]3 years ago
3 0

Answer:

First table

Step-by-step explanation:

We have to find the set of value which could be from a direct proportion.

We know that

Direct proportion :

When x is directly proportional to y

x\propto y

x=ky

Where k=Proportionality constant

k=\frac{x}{y}

K remain constant when x and y are in direct proportion

From first table

k=\frac{\frac{1}{2}}{6}=\frac{1}{12}

k=\frac{1}{12}

k=\frac{2}{24}=\frac{1}{12}

K=\frac{3}{36}=\frac{1}{12}

When x and y are both varies then ratio of x and y remain constant.Hence, it is in direct proportion.

From second table

k=\frac{0}{0}= not ]define

k=\frac{1}{1}=1

It is not direct proportion because k does not remain constant.

From third table

k=\frac{0}{2}=0

k=\frac{2}{4}=\frac{1}{2}

It is not direct proportion because k does not remain constant.

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4 : 3
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Three times the sum of a number and seven is two less than five times the number
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The answer for x is 1/13
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the performance score of 10 adults is recorded, and the results are 83 87 90 92 93 100 104 111 115 121 find the standard deviati
luda_lava [24]

Answer:

The standard deviation of the data set is \sigma = 12.7906.

Step-by-step explanation:

The Standard Deviation is a measure of how spread out numbers are. Its symbol is σ (the greek letter sigma)

To find the standard deviation of the following data set

\begin{array}{cccccccc}83&87&90&92&93&100&104&111\\115&121&&&&&&\end{array}

we use the following formula

                                             \sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }

Step 1: Find the mean \left( \overline{X} \right).

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

                                     Mean = \frac{Sum ~ of ~ terms}{Number ~ of ~ terms}

Mean = \frac{Sum ~ of ~ terms}{Number ~ of ~ terms}=\frac{83+87+90+92+93+100+104+111+115+121}{10} \\\\Mean = \frac{996}{10} =\frac{498}{5}=99.6

Step 2: Create the below table.

Step 3: Find the sum of numbers in the last column to get.

\sum{\left(x_i - \overline{X}\right)^2} = 1472.4

Step 4: Calculate σ using the above formula.

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 1472.4 }{ 10 - 1} } \approx 12.7906

3 0
3 years ago
ASAP PLZ!!!
lyudmila [28]

The solution has to be a value of x. Since you already have x, you just have to plug in the value and see what fits. In this case thats the third from the top:

5^2 - 10*5 + 25 = 0

25 - 50 + 25 = 0

0 = 0

Hope it helps!

7 0
3 years ago
The Print Shop provides copying services to the general public. The Print Shop has equipment which is capable of making 1,800 co
steposvetlana [31]

a) The financial analysis determining the acceptance of the special order is as follows:

Data and Financial Analysis:

Capacity of photocopier per hour = 1,800 copies

Practical capacity of equipment = 7 hours

Total copies in a day = 12,600 (1,800 x 7)

Steady demand per day = 10,000

Variable cost per copy = $0.22

Service price per copy = $0.25

Profit per copy = $0.03 ($0.25 - $0.22)

Normal profit based on steady demand of 10,000 = $300 ($0.03 x 10,000)

Profit based on maximum capacity of 12,600 = $378 ($0.03 x 12,600)

Price per copy for the special customer = $0.24

Profit per copy based on special price of $0.24 = $0.02 ($0.24 - $0.22)

Profit from special customer with 5,000 pages = $100 (5,000 x $0.02)

Profit from other probable customers = $228 (7,600 x $0.03)

Lost profit for accepting special order based on maximum capacity = $50 ($378 - $228 - $100)

Lost profit if order is <u>not accepted</u> and demand is only 10,000 copies = $78 ($378 - $300)

  • Therefore, the special order at $0.24 should be accepted.

b) The largest order from customer that the shop could accept = 5,000 + $50/$0.02

= 5,000 + 2,500

= 7,500 copies

Thus, if the customer orders 7,500 copies to be made, the shop can still realize a maximum profit of $378 by accepting orders for additional 5,100 (12,600 - $7,500) copies from others.

Learn more: brainly.com/question/22599880

7 0
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