-6/8...I guess so
Tell me if it is right or not
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
Step-by-step explanation:
the expression is equivalent with
5(3n-2)=15n-10
Commutative property of additiona☺☺
Hello!
First, you will need to subtract -2 from 4 (4-(-2)). You'll need to do this because to find the slope, you'll need to subtract y² w/ y1 or 4-(-2) and divide it by x² - x1 or -1-(-3). So once you set up the equation it'll look like this...
4-(-2)/-1-(-3)
Now after you've subtracted the numbers, your equation will look like this...
6/2
You'll then divide 6 by 2 and your slope will be 3
I hope this helps!
