Can someone please help

Mathematics

1 answer:

elena-s [515]2 years ago

5 0

Answer:

I think is b

Step-by-step explanation:

Ii just did the math and I think is b

You might be interested in

Find the slope and the equation for the line passing through the (-3,2 ) point with x-intercept at x=-4. and how do I find the e

WINSTONCH [101]

Well, the x-intercept is at -4, that means, the graph touches the x-axis at -4, or when x = -4, what's the value of "y" when that happens? well, if the graph touches the x-axis, the y-value has gone all the way down to 0, and thus y = 0, therefore the point at that x-intercept is ( -4, 0 )

so, what's the equation of a line that passes through (-3,2) and (-4,0)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -3}}\quad ,&{{ 2}})\quad 
% (c,d)
&({{ -4}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-4-(-3)}\implies \cfrac{0-2}{-4+3}
\\\\\\
\cfrac{-2}{-1}\implies 2
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-2=2[x-(-3)]
\\\\\\
y-2=2(x+3)\implies y-2=2x+6\implies y=2x+8$

3 0

3 years ago

In a rectangular coordinate plane what is the distance between points (-3,0) and (3,8)

zheka24 [161]

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:

$\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

"d" represents the distance and coordinates are expressed as follows: (x, y)

Let's go to the calculations.

$\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(3-(-3))^2+(8-0)^2}}\\\\ \mathsf{d=\sqrt{(3+3)^2+(8)^2}}\\\\ \mathsf{d=\sqrt{(6)^2+64}}\\\\ \mathsf{d=\sqrt{36+64}}\\\\ \mathsf{d=\sqrt{100}}\\\\ \underline{\mathsf{d=10}}$