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3 years ago

Find the distance between the points (-5, -10) and (2, 4).

Mathematics

2 answers:

Korvikt [17]3 years ago

8 0

Answer

15.652476

Reason: i used a calculator

riadik2000 [5.3K]3 years ago

6 0

Answer:

Distance between two points = 15.6525

Step-by-step explanation:

Solution :

Distance between two points =

√(2− -5)squared+(4− -10)squared

= √7+14

= √49+196

= √245 = 15.6525

Distance between points (-5, -10) and (2, 4) is 15.6525

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The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

2 years ago

2/3=x/6=9/y to find the value of y in this proportion you must divide 54 by

scZoUnD [109]

Answer:

You must divide $54$ by $4$

Step-by-step explanation:

we have

$\frac{2}{3}=\frac{x}{6}=\frac{9}{y}$

Step 1

Solve for x

$\frac{2}{3}=\frac{x}{6}$

$3x=6*2\\x=12/3\\x=4$

Step 2

Find the value of y

$\frac{x}{6}=\frac{9}{y}$

Substitute the value of x

$\frac{4}{6}=\frac{9}{y}$

$4y=9*6\\y=54/4\\y= 13.5$

therefore

You must divide $54$ by $4$

6 0

3 years ago

Read 2 more answers

Name three pairs that have 5 as there greatest common factor

Hitman42 [59]

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2 years ago

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Which polynomial represents the difference below?

Lera25 [3.4K]

Answer:

Step-by-step explanation:

distribute the parenthesis by - 1 and collect like terms

= 5x² + 9x + 3 - 6x² + 3x

= (5x² - 6x²) + (9x + 3x) + 3

= - x² + 12x + 3 → c

4 0