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mariarad [96]
4 years ago
7

In the photo, a locomotive has broken through the wall of a train station. During the collision, what can be said about the forc

e exerted by the locomotive on the wall?
Physics
1 answer:
Pavlova-9 [17]4 years ago
6 0

Answer:

Whether the force exerted by the locomotive on the wall was larger

Than the force the locomotive could exert on the wall.

Explanation:

The Newton's third law of motion States that every force have it's equal and opposite reaction force, whose magnitude is the same as the applied force. Therefore the magnitude of these opposite forces will be equal.

So we have;

F12=-F21

F12 is the force in a direction

-F21 is the force in the opposite direction.

Therefore we see that the magnitude of the force the locomotive exerts on the wall is equal to the one the wall exerts on the locomotive. Both magnitudes are equal but in opposite directions.

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A centrifugal pump discharges 300 gpm against a head of 55 ft when the speed is 1500 rpm. The diameter of the impeller is 15.5 i
Ksivusya [100]

Answer: Question 1: Efficiency is 0.6944

Question 2: speed of similar pump is 2067rpm

Explanation:

Question 1:

Flow rate of pump 1 (Q1) = 300gpm

Flow rate of pump 2 (Q2) = 400gpm

Head of pump (H)= 55ft

Speed of pump1 (v1)= 1500rpm

Speed of pump2(v2) = ?

Diameter of impeller in pump 1= 15.5in = 0.3937m

Diameter of impeller in pump 2= 15in = 0.381

B.H.P= 6.0

Assuming cold water, S.G = 1.0

eff= (H x Q x S.G)/ 3960 x B.H.P

= (55x 300x 1)/3960x 6

= 0.6944

Question 2:

Q = A x V. (1)

A1 x v1 = A2 x V2. (2)

Since A1 = A2 = A ( since they are geometrically similar

A = Q1/V1 = Q2/V2. (3)

V1(m/s) = r x 2π x N(rpm)/60

= (0.3937x 2 x π x 1500)/2x 60

= 30.925m/s

Using equation (3)

V2 = (400 x 30.925)/300

= 41.2335m/s

To rpm:

N(rpm) = (60 x V(m/s))/2 x π x r

= (60 x 41.2335)/ 2× π × 0.1905

= 2067rpm.

6 0
3 years ago
A 2.43ug particle moves at 1.97 x 108 m/s. What is its momentum?
Ira Lisetskai [31]

Answer:

0.48 kgm/s

Explanation:

m = mass of the particle = 2.43 μg = 2.43 x 10⁻⁶ x 10⁻³ kg = 2.43 x 10⁻⁹ kg

v  = velocity of the particle = 1.97 x 10⁸ m/s

p = momentum of the particle

momentum of the particle is given as

p = m v

inserting the values

p = (2.43\times 10^{-9})(1.97\times 10^{8})

p = 0.48 kgm/s

4 0
3 years ago
If a bowling ball is moving with acceleration of 15 m/s2 and has a mass of 10kg what is the force of the ball as it knocks down
Lina20 [59]

Answer:

150 newtons

Explanation:

F = ma

force = mass * acceleration

the mass is 10 kg, and the accelration is 15 m/s^2

10*15 = 150

the force unit that matches with meters/second and kg is newtons

F =ma

150 newtons = 10 kg * 15 m/s^2

6 0
3 years ago
The number of ______ always differs in atoms of different elements
zhenek [66]
The number of protons always differs in atoms of different elements.
8 0
3 years ago
Two friends, Joe and Sam, go to the gym together to strength train. They decide to start off with an exercise called flat bench
astra-53 [7]

Answer:

216.31 (the work done by gravity is -216.31) positive for going up.

Explanation:

We look at this question first by getting the right equation for <em>work</em>.

Which should be... W = F x D.

From this, we can do everything, we need the Force (F) first - the question tells us that Joe is lying on his back and moves his arms upward to raise the barbell. This means that he is countering the force of graving on the object.

What is the formula for the force of gravity on an object near the earth?

Right here --- F_{grav} = mg

m = the mass and...

g  =  the acceleration due to gravity which is <em>9.81 m/s2</em>

Before we plug things in though, we need to convert everything to SI units,

the weight is in kg - so we're good to go there, but the length of Joe's arms are in "cm" we need m or meters. Converting 70 cm to m = .7 m.

Now, we just put it all together - (31.5kg)(9.81m/s2)(.7m) =  216.31 J or 216.31 N m.

3 0
3 years ago
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