In a problem where a child is danger form drowning from a river who has a current of 3.1km/hr to east and the child is 0.6km fro the shore and the upstream is 2,5km from the dock. So base on the question the boat with a speed of 24.8 km/hr is 1.9 km because the child is 0.6 km off the dock so 2.5 minus 0.6
Answer:
b) 1.29 V
Explanation:
Potential Difference: This is the work done when one coulomb of charge moves from one point to another in an electric field
The expression for the potential difference is
Q = CV .................... Equation 1
Where Q = amount of charge, C = Capacitance of the capacitor, V = potential difference.
Making V the subject of the equation,
V = Q/C................. Equation 2
Given: Q = 4.5 µC = 4.5×10⁻⁶ C, C = 3.5 µF = 3.5×10⁻⁶ F
Substituting into equation 2
V = 4.5×10⁻⁶ /3.5×10⁻⁶
V = 1.2857 V
V ≈ 1.29 V.
Hence the right option is b) 1.29 V
Explanation:
w = (4.52 ± 0.02) cm, x = ( 2.0 ± 0.2) cm, y = (3.0 ± 0.6) cm. Find z = x + y - w and its uncertainty.
z = x + y - w = 2.0 + 3.0 - 4.5 = 0.5 cm
Dz = Dx + Dy + Dw = 0.2 + 0.6 + 0.02 = 0.82 rounding to 0.8 cm
So z = (0.5 ± 0.8) cm
Solution with standard deviations, Eq. 1b, Dz = 0.633 cm
z = (0.5 ± 0.6) cm
Notice that we round the uncertainty to one significant figure and round the answer to match.
