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Tanzania [10]
3 years ago
11

PLZZZ HELP

Physics
1 answer:
Doss [256]3 years ago
4 0

Answer/Explanation:

The weight of an object is defined as the force that is exerted due to the gravitational force.

Mathematically, it can be written as :

W = m g

Where

m is the mass of the object

g is the acceleration due to gravity

Also,  

We know that the value of g varies with respect to the location. At the equator, the value of g is less as compared to the poles.

The feature of an object that affects its weight are :

Mass of the object

Location of the object

How much force Earth exerts on the object

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Chegg Given that the mean radius of the Moon’s orbit is 3.84 x 108 m and its period is 2.36 x 106 sec, at what altitude above th
alukav5142 [94]

Answer:

The altitude of geostationary satellite is 3.58\times10^{7}\ m

Explanation:

Given that,

Radius of moon's orbit r=3.84\times10^{8}\ m

Time period T=2.36\times10^{6}\ sec

We need to calculate the orbital radius of geostationary satellite is

Using formula of time period

T=\sqrt{\dfrac{4\pi^2}{GM}a^3}

a=((\dfrac{GM}{4\pi^2})T^2)^{\dfrac{1}{3}}

Where, G = gravitational constant

M = Mass of earth

T = time period of geostationary satellite orbit

Put the value in to the formula

a=((\dfrac{6.67\times10^{-11}\times5.97\times10^{24}}{4\times\pi^2})\times(86160)^2)^{\dfrac{1}{3}}

a=4.217\times10^{7}\ m

We need to calculate the altitude of geostationary satellite

Using formula of altitude

h = a-R_{e}

Where, R = radius of earth

a = radius of geostationary satellite

Put the value into the formula

h =4.217\times10^{7}-6.38\times10^{6}

h =35790000\ m

h=3.58\times10^{7}\ m

Hence, The altitude of geostationary satellite is 3.58\times10^{7}\ m

4 0
3 years ago
What is the speed of a truck that travels 10 i’m in 10 minutes ?
fiasKO [112]

10km/10min is a legitimate speed. So is meters/sec, km/hour (kph), etc.  

Kph is very common for vehicles:  

10 km/10 min (60 min/hr) = 60 kph

7 0
3 years ago
At what displacement of a sho is the energy half kinetic and half potential? what fraction of the total energy of a sho is kinet
expeople1 [14]

As we know that KE and PE is same at a given position

so we will have as a function of position given as

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

also the PE is given as function of position as

PE = \frac{1}{2}m\omega^2x^2

now it is given that

KE = PE

now we will have

\frac{1}{2}m\omega^2(A^2 - x^2) = \frac{1}{2}m\omega^2x^2

A^2 - x^2 = x^2

2x^2 = A^2

x = \frac{A}{\sqrt2}

so the position is 0.707 times of amplitude when KE and PE will be same

Part b)

KE of SHO at x = A/3

we can use the formula

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

now to find the fraction of kinetic energy

f = \frac{KE}{TE} = \frac{A^2 - x^2}{A^2}

f = \frac{A^2 - (\frac{A}{3})^2}{A^2}

f_k = \frac{8}{9}

now since total energy is sum of KE and PE

so fraction of PE at the same position will be

f_{PE} = 1 - f_k

f_{PE} = 1 - (8/9) = 1/9

7 0
3 years ago
A wave has a frequency of 875 hz and a wavelength of 352 m. At what speed is this wave traveling 
Sonbull [250]

Answer:

308,000 or 30.8×10^3

Explanation:

v=f×lamda

v is ?, f is 875Hz, lamda is 352m

v=875×352

v=308,000

v=30.8×10^3 m/s

5 0
3 years ago
What is the equation for frequency, wavelength, and speed of a wave?
Nastasia [14]

Answer:

       λ = v/f

Explanation:

frequency=f

wavelength = λ

speed of a wave=v

7 0
3 years ago
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