Answer:
Decreases the time period of revolution
Explanation:
The time period of Cygnus X-1 orbiting a massive star is 5.6 days.
The orbital velocity of a planet is given by the formula,
v = √[GM/(R + h)]
In the case of rotational motion, v = (R +h)ω
ω = √[GM/(R + h)] /(R +h)
Where 'ω' is the angular velocity of the planet
The time period of rotational motion is,
T = 2π/ω
By substitution,
<em>T = 2π(R +h)√[(R + h)/GM] </em>
Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.
Answer:
Gravity is the centripetal force when the moon orbits the earth.
Answer: 
Explanation:
Given
Length of beam 
mass of beam 
Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude
Also, the beam starts rotating about its center
So, the moment of inertia of the beam is
Torque is the product of moment of inertia and angular acceleration
