Answer:
The altitude of geostationary satellite is 
Explanation:
Given that,
Radius of moon's orbit 
Time period 
We need to calculate the orbital radius of geostationary satellite is
Using formula of time period


Where, G = gravitational constant
M = Mass of earth
T = time period of geostationary satellite orbit
Put the value in to the formula


We need to calculate the altitude of geostationary satellite
Using formula of altitude

Where, R = radius of earth
a = radius of geostationary satellite
Put the value into the formula



Hence, The altitude of geostationary satellite is 
10km/10min is a legitimate speed. So is meters/sec, km/hour (kph), etc.
Kph is very common for vehicles:
10 km/10 min (60 min/hr) = 60 kph
As we know that KE and PE is same at a given position
so we will have as a function of position given as

also the PE is given as function of position as

now it is given that
KE = PE
now we will have




so the position is 0.707 times of amplitude when KE and PE will be same
Part b)
KE of SHO at x = A/3
we can use the formula

now to find the fraction of kinetic energy



now since total energy is sum of KE and PE
so fraction of PE at the same position will be


Answer:
308,000 or 30.8×10^3
Explanation:
v=f×lamda
v is ?, f is 875Hz, lamda is 352m
v=875×352
v=308,000
v=30.8×10^3 m/s