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romanna [79]
3 years ago
15

The length of the hypotenuse of a 30°-60°-90° triangle is 7. Find the perimeter

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0
Rules for a 30-60-90 right triangle:
hyp = 2 * short leg
Long leg = sqrt(3) * short leg
Given:
hyp = 7
7 = 2*short leg
divide both sides by 2
7/2 = short leg
long leg = sqrt(3) * short leg
long leg = sqrt(3) * (7/2)
long leg = 6.06
P= s1 + s2 + s3
P = 7 + 3.5 + 6.06
P = 16.56 units      (Decimal approximation)
P = 10.5 + 3.5sqrt(3) units       (Exact value)
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A rectangle has vertices a(1,2), B(1,7), c(4,7), d(4,2). what is the perimiter of the rectangle
aliina [53]

Answer:

16

Step-by-step explanation:

You see, if you were to plot these points, (1, 2) and (1, 7) would be 5 points away from each other. If you were to plot the points (4, 2) and (4, 7) those points would also be 5 points away from each other. Now, (1, 2) and (4, 2) are 3 points apart as well as (1, 7) and (4, 7). Therefore, 5 + 5 = 10, 3 + 3 = 6, and finally, 10 + 6 = 16!

7 0
3 years ago
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Select all ratios equivalent to <br> 22:10.<br><br> 11:5<br> 110:50<br> 33:15
saveliy_v [14]

Answer:

All the 3 choices are correct.

Step-by-step explanation:

11:5   11 divided by 22 is 1/2  and 5/10 is 1/2

110/50   110 divided by 22 is 5 and 50 divided by 10 is 5

33/15     33 divided by 22 is 1 1/2 and 15 divided by 10 is 1 1/2

5 0
3 years ago
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Find all zeros<br>f(x)=x^4+6x^3+173x^2+332x+164​
zheka24 [161]
The zeros are (-1,0)
6 0
3 years ago
Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.
hram777 [196]

The center of mass is mathematically given as

\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \  \ \  x \in(0,1)$ \\\end

We calculate the total mass of the system.

\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}

Step 03: Calculate the moment of the system.

\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}

we calculate the center of mass.

\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

Read more about the center of mass.

brainly.com/question/27549055

#SPJ1

8 0
2 years ago
Select all of the following that are ordered pairs of the given function.
Tatiana [17]
F(x) is the same as y.......so basically ur subbing in ur points into the equation to see if it comes out equal.

f(x) = 3 - 2x.....(-2,-1)....x = -2 and f(x) = -1
-1 = 3 - 2(-1)
-1 = 3 + 2
-1 = 5.....this is not true, so it is not a solution

and that is how to do this problem.....

(-1,5)......this IS a solution
(0,3)......this IS a solution
(1,0)...this IS NOT a solution
(2,-1)...this IS a solution

8 0
3 years ago
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