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4 years ago

Write a conjecture that describes the pattern in each sentence -5, 10, -20, 40, -80

1 answer:

3 0

This pattern is multiply by -2. Your conjecture or conclusion will be that it changes by a multiple of negative two each time. Half the numbers are positive because if you multiply two negatives, they equal a positive. Hope this helps.

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Find the odds of each of the following events. (a) an event E with Pr(E) = 4/7 (b) an event E with Pr(E) = 0.6 (a) The odds are

Dafna1 [17]

Answer:

(a) The odds of event E is 4/3.

(b) The odds of event E is 3/2.

Step-by-step explanation:

Formula for probability of an event:

$Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Formula for odds of an event:

$odds=\frac{\text{Favorable outcomes}}{\text{Unfavorable outcomes}}$

(a)

It is given that

$P(E)=\frac{4}{7}$

The probability of unfavorable event

$P(E')=1-P(E)=1-\frac{4}{7}=\frac{3}{7}$

Odds of event E is

$odds=\frac{P(E)}{P(E')}$

$odds=\frac{\frac{4}{7}}{\frac{3}{7}}$

$odds=\frac{4}{3}$

Therefore the odds of event E is 4/3.

(b)

It is given that

$P(E)=0.6$

The probability of unfavorable event

$P(E')=1-P(E)=1-0.6=0.4$

Odds of event E is

$odds=\frac{P(E)}{P(E')}$

$odds=\frac{0.6}{0.4}$

$odds=\frac{3}{2}$

Therefore the odds of event E is 3/2.

3 0

3 years ago

Im confused please help

Hitman42 [59]

156/9 = 17.3

So Lina can make about 17 beaded bracelets with 156 beads.

Hope this Helps!!

3 0

3 years ago

A search committee is formed to find a new software engineer.

Free_Kalibri [48]

Answer:

(a) 1,902,231,808,400

(b) 84

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\cdot(n-k)!}$

(a)

Compute the number of ways to select 9 applicants from 100 as follows:

${100\choose 9}=\frac{100!}{9!\cdot(100-9)!}$

$=\frac{100!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92\times 91!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92}{9!}\\\\=1902231808400$