How do I find out a mortgage payment on a home

The accompanying data set consists of observations on shower-flow rate (L/min) for a sample of n = 129 houses: 4.6 12.1 7.1 7.0

Gennadij [26K]

Answer:

Step-by-step explanation:

For n=129 and with leaf unit = 0.1, the stem and leaf chart of the given data on Shower-flow rate (L/min) is as follows:

2 28

Stem leaves

3----------1344567789

4----------01356889

5----------00001114455666789

6----------0000122223344456667789999

7----------00012233455555668

8----------02233448

9----------012233335666788

10----------2344455688

11--------- 2335999

12---------- 17

13-------- 9

14--------36

15---------- 0035

16---------None

17---------None

18 ----------3

* From steam and leaf chart we note that minimum Shower flow rate is 2.2 whereas maximum is 18.3 L/mim. Further typical or representative rate is 7.0 L/min.

* The display of data on steam and leaf chart shows that data is positively skewed means concentration of data on left side or lower value side is high as compared to other side.

* Distribution is not symmetric rather very clear positive skew ness is observed through steam and leaf chart. Even distribution is Unimodal.

* From steam and leaf chart is indicative to conclude that the highest observation 18.3 is outlier.

3 0

2 years ago

Orthogonally diagonalize the matrix, giving an orthogonal matrix P and a diagonal matrix D. To save time, the eigenvalues are

alexgriva [62]

Answer:

$P=\left(\begin{array}{ccc}-\frac{2}{3}&-\frac{2}{3}&\frac{1}{3}\\\frac{1}{\sqrt{5}}&0&\frac{2}{\sqrt{5}}\\-\frac{4}{3\sqrt{5}}&\frac{\sqrt{5}}{3}&\frac{2}{3\sqrt{5}}\end{array}\right)$

Step-by-step explanation:

It is a result that a matrix $A$ is orthogonally diagonalizable if and only if $A$ is a symmetric matrix. According with the data you provided the matrix should be