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2 years ago

What is the area of the trapezoid? [A = 1 2 (b1 + b2)h]

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

7 0

The area of a trapezium is
A = (a+b)*h/2
24 + 18 = 46 * 5 = 230 / 2 = 115

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Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply

kykrilka [37]

$\cos(2x) = \cos(x)$

Solution (1)

$2x = x + 2k\pi$

$2x - x = 2k\pi$

$x = 2k\pi$

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

$2x = - x + 2k\pi$

$2x + x = 2k\pi$

$3x = 2k\pi$

$x = \frac{2k\pi}{3}$

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

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2 years ago

What's the y intercept of 4x+3y=9

8090 [49]

X-intercept - (9/4, 0)
Y-intercept - (0, 3)

5 0

3 years ago

Read 2 more answers

The formula for the area of a circle is A = πr^2. Which equation shows the formula in terms of r?

Julli [10]

$A=\pi r^2\\\\\pi r^2=A\ \ \ |\text{divide both sides by}\ \pi\\\\r^2=\dfrac{A}{\pi}\ \ \ \ |\text{square root both sides}\\\\r=\sqrt{\dfrac{A}{\pi}}$

6 0

3 years ago

Work out m and c for the line: y = X – 2

RUDIKE [14]

Y = mx + c therefore
m = 1
c = -2

4 0

2 years ago

Given point B is located at

ELEN [110]

Answer: $\Large\boxed{Point~B'~=~(-4,~-2)}$

Step-by-step explanation:

Given information

Point B = (-2, -4)

Reflection line: y = x

Concept:

When reflecting over the line y = x, the position of y and x in the original coordinate switches places.

This is because it is " y = x ", assuming that they could interchange

Find the coordinate of Point B'

Original (x, y) = (-2, -4)

Point B' = (x', y') = (y, x) = $\Large\boxed{(-4,~-2)}$

Please refer to the attachment below for a graphical understanding

Hope this helps!! :)

Please let me know if you have any questions

4 0

1 year ago