All categories

3 years ago

Evaluate the expression. 5 - (4 - 2 - (6-6)) 8 2 5 3

Mathematics

2 answers:

Elodia [21]3 years ago

8 0

Answer:

Step-by-step explanation:

Simplify the following:

5 - (4 - 2 - (6 - 6))

6 - 6 = 0:

5 - (4 - 2 - 0)

-0 = 0:

5 - (4 - 2 + 0)

4 - 2 + 0 = 4 - 2:

5 - 4 - 2

4 - 2 = 2:

5 - 2

5 - 2 = 3:

Answer: 3

Doss [256]3 years ago

3 0

Answer: 3

Step-by-step explanation:

5−(4−2−(6−6))

You might be interested in

Which values are solutions to the inequality below? <br><br>Check all that apply.<br><br>x2 25

lawyer [7]

B D and E
Hdhdhsmsndnsndnnsjsbdndndndhdjdndndhf

3 0

3 years ago

How many inches is 35 yards?

Tomtit [17]

Answer:

1260 inches

Step-by-step explanation:

Calculator

7 0

1 year ago

A scuba diver descends 63 feet in 18 seconds.

Elanso [62]

Answer:

3.5

Step-by-step explanation:

the answer is 3.5 because when you divide 63 and 18 you get 3.5

5 0

3 years ago

How do you find the distance between two coordinate points on the graph?

borishaifa [10]

Answer:

point of intercept

Step-by-step explanation:

measure x and y axis to see where they cross

6 0

3 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago