Answer:
yes it does
Step-by-step explanation:
because the equation y=9x does not have a y-intercept (all slopes come in the form y=mx+b -- it can be written differently though) and since there is no 'b' that means the y-intercept is 0. So whenever there is no y-intercept, the slope starts at 0.
I need to see the diagram in order to answer your question.
50 Dollars For The Member-Ship
2 Dollars For The Class (C)
Y=Total (unknown because you dont know how may classes)
Y=50(C)
Answer:
1
Step-by-step explanation:
Question 1
probability between 2.8 and 3.3
The graph of the normal distribution is shown in the diagram below. We first need to standardise the value of X=2.8 and value X=3.3. Standardising X is just another word for finding z-score
z-score for X = 2.8

(the negative answer shows the position of X = 2.8 on the left of mean which has z-score of 0)
z-score for X = 3.3

The probability of the value between z=-0.73 and z=0.49 is given by
P(Z<0.49) - P(Z<-0.73)
P(Z<0.49) = 0.9879
P(Z< -0.73) = 0.2327 (if you only have z-table that read to the left of positive value z, read the value of Z<0.73 then subtract answer from one)
A screenshot of z-table that allows reading of negative value is shown on the second diagram
P(Z<0.49) - P(Z<-0.73) = 0.9879 - 0.2327 = 0.7552 = 75.52%
Question 2
Probability between X=2.11 and X=3.5
z-score for X=2.11

z-score for X=3.5

the probability of P(Z<-2.41) < z < P(Z<0.98) is given by
P(Z<0.98) - P(Z<-2.41) = 0.8365 - 0.0080 = 0.8285 = 82.85%
Question 3
Probability less than X=2.96
z-score of X=2.96

P(Z<-0.34) = 0.3669 = 36.69%
Question 4
Probability more than X=3.4

P(Z>0.73) = 1 - P(Z<0.73) = 1-0.7673=0.2327 = 23.27%