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GalinKa [24]
2 years ago
10

What is the total amount paid for a $60 meal with a 15% tip and 8% tax?

Mathematics
1 answer:
Taya2010 [7]2 years ago
4 0

Answer:

I believe it would be 73.8 or if they are rounding up 74.

Step-by-step explanation:

15% of 60 is *9* and 8% of 60 is *4.8*

9+4.8=13.8

13.8+60=73.8.

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A 5×5×5 wooden cube was painted and then sawed into 1×1×1 cubes. How many 1×1×1 cubes are there? HELPPPPP!!!!!!!!!!!!!!!!!!!!!!
Shalnov [3]

Answer:

125

Step-by-step explanation:

1 x 1  x 1 = 1

5 x 5 x 5 = 125

125 / 1 = 125

125 is your answer

6 0
3 years ago
ENCHI
BabaBlast [244]

Given :

A T.V. is measure by its diagonal.

To Find :

If the height of a 60 inch  T.V. is 32 inches, what is the width.

Solution :

We know, T.V. is rectangular in shape and angle between two sides of rectangular is 90° .

Let, width of T.V. is x.

Applying Pythagoras theorem in sides, we get :

height^2 + width^2 = hypotenuse^2\\\\23^2 + x^2 = 60^2\\\\x = \sqrt{3600 -529 }\\\\x = 55.42 \ inches

Therefore, width of T.V. is 55.42 inches.

7 0
3 years ago
Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -
irina [24]

Answer:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Step-by-step explanation:

Given

T:R^3->R^2

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

Required

Find the standard matrix

The standard matrix (A) is given by

Ax = T(x)

Where

T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

Ax = T(x) becomes

Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

The x on both sides cancel out; and, we're left with:

A = [T(e_1)\ T(e_2)\ T(e_3)]

Recall that:

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

In matrix:

(a,b) is represented as: \left[\begin{array}{c}a\\b\end{array}\right]

So:

T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]

T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]

T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]

Substitute the above expressions in A = [T(e_1)\ T(e_2)\ T(e_3)]

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Hence, the standard of the matrix A is:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

6 0
3 years ago
A software company decided to conduct a survey on customer satisfaction. Out of 564 customers who participated in the online sur
nikklg [1K]

Answer:

z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8  

p_v =2*P(z  

Step-by-step explanation:

Information given

n=564 represent the sample selected

X=51 represent the number of people who rated the overall services as poor

\hat p=\frac{51}{564}=0.0904 estimated proportion of people who rated the overall services as poor  

p_o=0.1 is the value to compare

z would represent the statistic

Hypothsis to analyze

We want to analyze if the proportion of customers who would rate the overall car rental services as poor is 0.1, so then the system of hypothesis are:  

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

The statistic for a one z test for a proportion is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8  

And the p value since we have a bilateral test is given b:

p_v =2*P(z  

3 0
3 years ago
I was gone today at school and know I have no clue what to do! Please please help me!!
krek1111 [17]
What do you have to find?
do you just need to solve the problem with those numbers?
5 0
3 years ago
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