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3 years ago

How many radians are contained in the angle AOT in the figure? Round your answer to three decimal places.

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

4 0

1 radian = 57.3 degrees

60 <span>÷ 57.3 = 1.047
</span>

correct answer: C

Whitepunk [10]3 years ago

4 0

Answer:

Option C. 1.047 radians

Step-by-step explanation:

We have to find the measure of angle AOT in radians.

To convert measure of an angle from degree to radians we use the formula

$\text{radians}=\frac{\pi(\text{degrees})}{180}$

= $\frac{\pi(60)}{180}=\frac{\pi }{3}$

(Since measure of angle AOT is 60°)

= $\frac{3.14}{3}$ (since π = 3.14)

= 1.047 radians

Therefore, option C. 1.047 radians is the correct option.

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harina [27]

Answer:

12.81 miles

Step-by-step explanation:

You need to use the Pythagorean Theorem to draw a triangle.

10 squared + 8 squared = c squared.

100 + 64 = c squared

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find the square root of 164:

12.81.

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3 years ago

What is the equation of the following line you should scroll down to see all Answer options

lilavasa [31]

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1 year ago

1/12 ? 1 =1/12 which is it multiply or divide. Please explain how you got it.

Ivanshal [37]

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6 0

3 years ago

33 1/3% of what amount is 33?

vlada-n [284]

Answer:

Yes the amount is 33............

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3 years ago

The length of a rectangular pool is to be four times its width and a sidewalk 6ft wide will surround the pool. If a total area o

natita [175]

Answer:

52 feet by 13 feet.

Step-by-step explanation:

Given:

The length of a rectangular pool is to be four times its width.

Sidewalk is 6 feet wide will surround the pool.

If a total area of 1600 square feet has been set aside for the area of the pool and the sidewalk.

Question asked:

What are the dimensions of the pool?

Solution:

Let width of a rectangular pool = $x$

Then the length of a rectangular pool will be = $4x$

$Area\ of \ rectnagle= length\times breadth$

$=x\times4x\\ \\ =4x^{2}$

Combined length of pool and the sidewalk = length of pool + width of sidewalk + width of sidewalk

Combined length of pool and the sidewalk = $4x+6+6=4x+12$

Similarly, Combined width of pool and the sidewalk = $x+6+6=x+12$

Combined area of pool and the sidewalk = 1600

$Combined\ lengthh\times Combined\ r=breadth=1600\\ \\ (4x+12)(x+12)=1600\\ \\ 4x(x+12)+12(x+12)=1600\\ \\ 4x^{2} +48x+12x+144=1600\\ \\ 4x^{2} +60x+144=1600$

Subtracting both sides by 144

$4x^{2} +60x=1456\\ \\ 4x^{2} +60x-1456=0\\ \\ Taking\ 4\ as\ common\\ \\ x^{2} +15x-364=0\\ \\ x^{2} +28x-13x-364=0\\ \\ x(x+28)-13(x+28)=0\\ \\ x+28=0,x-13=0\\ \\ x=-28,x=13$

Since dimensions can never be in negative, hence $x=13$

Width of a rectangular pool = $x$ = 13 feet

The length of a rectangular pool will be = $4x$ = $4\times13=52\ feet$

Therefore, the dimensions of the pool are 52 feet by 13 feet.

8 0

3 years ago